Factor x3 + x2 + 2x + 2, by grouping. Group the first two terms and the last two terms. Then factor.
First, factor x3 + x2 by pulling out an x2 term: x2(x + 1)
Second, factor 2x + 2 by pulling out a 2: 2(x + 1)
So, you now have:
x2(x + 1) + 2(x + 1)
If you have factored correctly, the terms inside the parentheses should be the same.
Now regroup.
ANS: (x + 1)(x2 + 2)
2(x^2 + 2)(x + 3)
(2x+3)(2x+4)
The quotient works out as: x^2+2x+4 and there is a remainder of -3
(2x - 1)(5x + 8)
2 (2x2 + 2x + xy + y ) it's 2 (2x + y)(x + 1) if you're doing A+
2x(x^2+x-6)
The answer is (2x^2+3)(4x+1)
Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)
2x3 + 2x2 = 2x2 * (x + 1)
2(x^2 + 2)(x + 3)
200x
(x - 1)(2x^2-1)
2x^2y^3(4x^2 - 3xy + 1)
(2x3 - x2) = x2 (2x - 1)
4
(2x+3)(2x+4)
(x + 1)(2x + 5)