The answer is (2x^2+3)(4x+1)
8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
4x3+10x2-6x 2x(2x2+5x-3) 2x(2x-1)(x+3)
3
2x^2y^3(4x^2 - 3xy + 1)
The answer is (2x^2+3)(4x+1)
8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
2x3 + 2x2 = 2x2 * (x + 1)
The quotient works out as: x^2+2x+4 and there is a remainder of -3
4x3+10x2-6x 2x(2x2+5x-3) 2x(2x-1)(x+3)
3
2x^2y^3(4x^2 - 3xy + 1)
(2x3 - x2) = x2 (2x - 1)
2x(x−6)(x+1)
2x2 + 2x = 2x(x+1)
4
(2x + 1)(4x^2 - 2x + 1)