Q: Factor pair of 56 for which the difference of the two is 1?

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(+7 and +8) and (-7 and-8)

Yes, 28 is a factor of 56, because 56/28 is a whole number.

There is insufficient information to answer the question unambiguously. The two numbers could be any of the following pairs: (7,8), (14,8), (28,8) or (56,8).

No. 56 is a multiple of 7 which also means that 7 is a factor of 56.

28 is a factor of 56, and 28 is also a factor of itself. So the highest common factor of 28 and 56 is 28.

Related questions

By starting with a different factor pair. 56 28,2 14,2,2 7,2,2,2 56 4,14 2,2,14 2,2,2,7

-7 and -8 is one possible pair.

Factors of 45: 1 3 5 9 15 45 Factors of 56 : 1 2 4 7 8 14 28 56 The GCF of 45 and 56 is 1 Another way to approach this is to look at the difference between 45 and 56, which is 11. The greatest common factor of two numbers cannot be larger than the difference between the two numbers. The greatest common factor of two numbers must also be a factor of the difference between the numbers. The difference, 11, is a prime number, so the greatest common factor must be either 11 or 1. Since the numbers are not evenly divisible by 11, the greatest common factor is 1.

56 and 105

56 and 72

The second one.

56 and 112, among many others.

8 is the GCF of 56 and 72.

No - 5 is a prime number, its only two positive integer factors are 1 and 5.

28

Find a common factor of 21 and 56 and divide both by that factor to give two new numbers. If necessary, repeat the process with a common factor of these two numbers and so on. This looping can be done in one step if you can find the greatest common factor. So, for 21 and 56, the GCF = 7 So 21/56 = (21/7) / (56/7) = 3/8

(+7 and +8) and (-7 and-8)