3p+7 = 16+2p 3p-2p = 16-7 p = 9
8 + 5p + 7q + 9 + 3p Reordering: 8 + 9 + 5p + 3p + 7q Combine like terms: 17 + 8p + 7q
-5 + 3p - p = -5 + 2p
We're guessing that what you really want to know is the value of 'p'that makes the statement true. Here's how to find it:3p + 4 = -14Subtract 4 from each side:3p = -18Divide each side by 3:p = -6
3p + 6p = (3 + 6)p = 9p
Assuming this is your original formula: -3p3+ 5p + -2p2 + -4 - -12p + 5 - -8p3You combine like terms, where the p exponent is the same, to produce:5p3 - 2p2 + 17p + 1
3p
3p
Let f(X)=2X2+6X+3 So f(-p)=f(2q) or 2p2-6p+3=8q2+12q+3 or p2-3p=4q2+6q or p2-4q2=3p+6q or (p+2q)(p-2q)=3(p+2q) so p-2q=3
3p+52
3p+7 = 16+2p 3p-2p = 16-7 p = 9
This quadratic expression can not be factored because its discriminant is less than zero.
3p+5+p = -23 3p+p = -23-5 4p = -28 p = -7
8 + 5p + 7q + 9 + 3p Reordering: 8 + 9 + 5p + 3p + 7q Combine like terms: 17 + 8p + 7q
-5 + 3p - p = -5 + 2p
Add them together: 02p+3p = 5p
p2 + 3p = p (p + 3)