0
Oh, dude, you want some odd numbers that add up to 143? Sure, let's make this a party! So, if we call the first odd number x, the next one would be x+2, and the one after that would be x+4. If you add them up, you get 3x+6=143. Solve that bad boy, and you'll find x=45. So, the numbers are 45, 47, and 49. Party on!
Still curious? Ask our experts.
Chat with our AI personalities
Rene
Judy
JordanLet's denote the three consecutive odd integers as x, x+2, and x+4. Since they are odd, their sum can be represented as 3x + 6. We know that this sum is equal to 143, so we can set up the equation 3x + 6 = 143. Solving for x, we get x = 45. Therefore, the three consecutive odd integers are 45, 47, and 49.
Sure thing, darling. Let's break it down. If we call the first odd integer x, the next odd integer would be x+2, and the one after that would be x+4. Adding them up, we get x + (x+2) + (x+4) = 143. Solve that bad boy and you'll find the consecutive odd integers are 47, 49, and 51. Keep slaying those math problems!
Add your answer:
Earn +20 pts
The sum of the squares of two consecutive negative odd integers is 74 Find the integers?
The two consecutive negative odd integers having 74 as the sum of their squares are -5 and -7.
Two consecutive odd integers such that their product is 143 more than 5 times their sum?
17 and 19.
Find 2 consecutive odd integers that have a sum of 123?
There is a set of two consecutive integers that have a sum of 123; one odd and one even. They are 61 and 62.
Find two consecutive odd integers whose sum is 28?
The integers are 13 and 15.
Find three consecutive odd integers that have a sum that is 45?
13,15,17
