Oh, dude, you want some odd numbers that add up to 143? Sure, let's make this a party! So, if we call the first odd number x, the next one would be x+2, and the one after that would be x+4. If you add them up, you get 3x+6=143. Solve that bad boy, and you'll find x=45. So, the numbers are 45, 47, and 49. Party on!
Let's denote the three consecutive odd integers as x, x+2, and x+4. Since they are odd, their sum can be represented as 3x + 6. We know that this sum is equal to 143, so we can set up the equation 3x + 6 = 143. Solving for x, we get x = 45. Therefore, the three consecutive odd integers are 45, 47, and 49.
Sure thing, darling. Let's break it down. If we call the first odd integer x, the next odd integer would be x+2, and the one after that would be x+4. Adding them up, we get x + (x+2) + (x+4) = 143. Solve that bad boy and you'll find the consecutive odd integers are 47, 49, and 51. Keep slaying those math problems!
17 and 19.
The two consecutive negative odd integers having 74 as the sum of their squares are -5 and -7.
There is a set of two consecutive integers that have a sum of 123; one odd and one even. They are 61 and 62.
The integers are 13 and 15.
13,15,17
The two consecutive, odd integers whose product equals 143 are 11 and 13.
11 and 13
Their product is 143.
find the two consecutive odd integers with a sum of 152
The sum of two consecutive odd integers is an even number. There is no possible answer to this question.
The four consecutive odd integers are 43 + 45 + 47 + 49 = 184
17 and 19.
The two consecutive negative odd integers having 74 as the sum of their squares are -5 and -7.
They are 2n+2
There is a set of two consecutive integers that have a sum of 123; one odd and one even. They are 61 and 62.
The integers are 11, 13 and 15.
The integers are 13 and 15.