13
9 and 10
The digits that add up to 10 are 1 and 9, 2 and 8, 3 and 7, and 4 and 6. This is because when you add these pairs of digits together, they equal 10. For example, 1 + 9 = 10, 2 + 8 = 10, and so on. These pairs are known as complementary pairs in mathematics.
No, there are an infinite number of integers. So, there would be an infinite (infinity/2-1) number of positive integers. And, there would be an infinite (infinity-10) number of integers greater than ten.
33
10-11-12
You add one at a time. For example, if you want to find three consecutive integers, starting with 10, you add 1 at a time to get 10 (the initial number), followed by 11 and 12.
The sum of the first 10 positive integers 1,2,3,4,5,6,7,8,9 and 10 is 55. The sum of the first 10 negative integers -1,-2,-3,-4,-5,-6,-7,-8,-9 and -10 is -55. The sum of the first 10 positive plus the sum of the first 10 negative integers is 0
5 and 10
Integers are whole numbers (including zero) and their negatives. I = {..., -2, -1, 0, 1, 2, ...} The positive integers are restricted to just: P = {1, 2, 3, ...} The two digit numbers in this set begin at 10 and end at 99. To count them, simply subtract and add one: 99 - 10 + 1 = 90. Or, count starting at 11 and you'll end up with 89, then add one more for 10 to get 90. :)
-3
The positive integers less than 11 are the natural numbers 1-10.That is to say 1,2,3,4,5,6,7,8,9 and 10.
Use a number line for example: -5 _ _ _ _ 0 _ _ _ _ 5 if you have -5 and you add 10 then you will go up ten on the number line. (the lines are spots for numbers) so -5+10=5
It isn't. 5 - 10 = -5
10 of them.
641
The sum of the digits is 6.
The sum of the first 10 positive integers, using the formula N1 + (N1 + 1) + ... + N2 = N2 * (N2 + 1) / 2 - (N1 - 1) * N1 / 2 is: 55