Using two positive integers to add up to 10:1 + 92 + 83 + 74 + 65 + 56 + 47 + 38 + 29 + 1
9 and 10
No, there are an infinite number of integers. So, there would be an infinite (infinity/2-1) number of positive integers. And, there would be an infinite (infinity-10) number of integers greater than ten.
33
10-11-12
You add one at a time. For example, if you want to find three consecutive integers, starting with 10, you add 1 at a time to get 10 (the initial number), followed by 11 and 12.
Using two positive integers to add up to 10:1 + 92 + 83 + 74 + 65 + 56 + 47 + 38 + 29 + 1
Integers are whole numbers (including zero) and their negatives. I = {..., -2, -1, 0, 1, 2, ...} The positive integers are restricted to just: P = {1, 2, 3, ...} The two digit numbers in this set begin at 10 and end at 99. To count them, simply subtract and add one: 99 - 10 + 1 = 90. Or, count starting at 11 and you'll end up with 89, then add one more for 10 to get 90. :)
5 and 10
-3
The sum of the first 10 positive integers 1,2,3,4,5,6,7,8,9 and 10 is 55. The sum of the first 10 negative integers -1,-2,-3,-4,-5,-6,-7,-8,-9 and -10 is -55. The sum of the first 10 positive plus the sum of the first 10 negative integers is 0
Use a number line for example: -5 _ _ _ _ 0 _ _ _ _ 5 if you have -5 and you add 10 then you will go up ten on the number line. (the lines are spots for numbers) so -5+10=5
The positive integers less than 11 are the natural numbers 1-10.That is to say 1,2,3,4,5,6,7,8,9 and 10.
It isn't. 5 - 10 = -5
10 of them.
The sum of the digits is 6.
641