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Of 157 students how many could be put equaly in 5 classes?
If a number is divisible by 5, it either ends in a 0 or a 5. Since this doesn't end in either, we know it isn't divisible by 5. We should find the next lowest number that is divisible by 5. Since 155 ends in a five, we know it is divisible by 5, and because this is the closest number below 157 that is divisible by 155, we know this is the greatest number of students that could be put equally into 5 classes. Alternatively, we can divide 157 by 5, and we get 31.4. Since we only want something that divides evenly by 5, we round this down to 31, then multiply by 5 to get 155.
Why does a rational number plus an irrational number equal an irrational number?
from another wikianswers page: say that 'a' is rational, and that 'b' is irrational. assume that a + b equals a rational number, called c. so a + b = c subtract a from both sides. you get b = c - a. but c - a is a rational number subtracted from a rational number, which should equal another rational number. However, b is an irrational number in our equation, so our assumption that a + b equals a rational number must be wrong.
What equation represents a line that is parallel to the line reprensented by the equation y equals -2 plus 5?
I assume the question should be y = -2x + 5? The equation of a line that is parallel to that line is any line that begins 7 = -2x ... after the -2x any number may be added or subtracted. Parallel lines have the same slope. In the original equation, the slope is -2.
Explain why the sum of three consecutive integers is divisible by three?
Here are some consecutive odd integers. All must follow this form: x+x+2+x+2=3x + 6 6 is divisible by 3. So is 3x. If you add two integers that are divisible by 3, it is still divisible by three. The question is not about odd integers, but consecutive integers. This should be x + x+1 + x+2 =3x+3 A bit simpler would be the three in a row : x-1, x, x+1 which add up to 3x which can be divided by 3.
How do you subtract a whole number from a fraction?
In order to subtract a fraction from a whole number one should take the bottom number from a fraction, for example if the fraction was 1 10th then the bottom number would be 10. The whole number should be divided by the bottom number, then the top number equivalent removed from the total whole number and this will leave the fraction number once the fraction has been subtracted.
What number should be subtracted from 63700 in order to make it exactly divisible by 18?
To find the number that should be subtracted from 63700 to make it exactly divisible by 18, first, calculate the remainder when 63700 is divided by 18. Dividing 63700 by 18 gives a quotient of 3538 and a remainder of 16. Therefore, to make 63700 divisible by 18, you need to subtract this remainder (16) from 63700. Thus, subtracting 16 will yield 63684, which is divisible by 18.
What is the least number that should be subtracted from 18448 to make it exactly divisible by 48?
It is: 16 because 18448-16 = 18432 and 18432/48 = 384
What least number should be subtracted from 86295031 so that the remainder is exactly divisible by 582?
To find the least number to be subtracted from 86295031 so that the remainder is divisible by 582, we first determine the remainder of 86295031 when divided by 582. Calculating (86295031 \mod 582) gives a remainder of 505. Therefore, to make the number exactly divisible by 582, we need to subtract this remainder, resulting in (505). Thus, the least number to subtract is 505.
What least number should be subtracted from 23483 to make it divisible by 10?
To make a number divisible by 10, its last digit must be 0. The last digit of 23483 is 3. Therefore, to make it divisible by 10, you should subtract 3 from 23483. This means the least number that should be subtracted is 3.
What least number should be subtracted from 789 so that the result is exactly divisible by 56?
To determine the least number to be subtracted from 789 to make it divisible by 56, first, calculate the remainder when 789 is divided by 56. Performing the division, 789 ÷ 56 gives a quotient of 14 and a remainder of 5. To make 789 divisible by 56, subtract this remainder from 56, which is 56 - 5 = 51. Therefore, the least number to be subtracted from 789 is 51.
Find the least number that should be subtracted from 1000 so that 30 divides the difference exactly?
which least number should be subtracted from 1000 so that 30 divides the difference exactly
What is the least number that should be subtracted from 27836 so that it is exactly divisible by 56?
27836/56 gives 497 and 4 as quotient and remainder Dividend- remainder =27836-4 = 27832 which is divisible by 56. So the least no that to be subracted is 4
What should be subtracted from 32575 to make it exactly divisible by 9?
32575/9 gives 3619 as quotient 4 as remainder. now from 32575 subtract the remainder 4 that is 32571. this is divisible by 9. 4 should be
What least number should be subtracted from it to make it divisible by?
It would help if you could insert the relevant numbers in the copy/paste!
What is the least number that should be subtracted from 832 to make it exactly divisible by 48?
832/48 gives 17 as quotient and 16 as remainder. Dividend-remainder=divisor*quotient 832-16 = 48*17 which is 816 that is divisible by 48. So 16 to be subracted.
What is the least number that should be added to 924 to make it exactly divisible by 48?
To find the least number that should be added to 924 to make it exactly divisible by 48, we need to find the remainder when 924 is divided by 48. The remainder is 12. Therefore, the least number that should be added to 924 to make it exactly divisible by 48 is 48 - 12, which equals 36.
What should be subtracted from number 2789 to make it divisible by 10?
2,789/10= 2,78.9. Just move the decimal place over one spot. So, if the answer has to be a whole number, not a fraction, then please subtract 9 from the number to get 2,780. No fraction.
