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Let the first consecutive integer be x. So that:

the second integer is x + 1,
the third integer is x + 2, and
the fourth integer is x + 3.

We have:

(x + 1) + (x + 3) = 132
2x + 4 = 132
2x = 128
x = 64 the first integer
Thus, the four consecutive integers are 64, 65, 66, and 67.

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