Let the first consecutive integer be x. So that:
the second integer is x + 1,
the third integer is x + 2, and
the fourth integer is x + 3.
We have:
(x + 1) + (x + 3) = 132
2x + 4 = 132
2x = 128
x = 64 the first integer
Thus, the four consecutive integers are 64, 65, 66, and 67.
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
The sum of the squares of two consecutive positive even integers is 340. Find the integers.
Find 2 consecutive ODD integers whose sum is -88 ANSWER: -45, -43
They are 28, 29 and 30.
The integers are 13 and 15.
64 65 66 67
34, 36, 38 and 40. The second and fourth are 36 and 40 which sum to 76. Another possible solution is 42, 40, 38 and 36.
find the two consecutive odd integers with a sum of 152
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
The sum of the squares of two consecutive positive even integers is 340. Find the integers.
9,10,11,12
9240 is the product of the three consecutive integers 20, 21, and 22.
The product of two consecutive integers is 132. Find the two integers. They are: 11*12 = 132
1,2,3,4
The numbers are 65 and 67.
Find 2 consecutive ODD integers whose sum is -88 ANSWER: -45, -43
The integers are -34 and -33.