the domain is when the denominator of the problem is set to zero... but i am not sure how to find the range
Use the function to find the image of each point in the domain. The set of values that you get will be the range. If the function is well behaved, you will not have to try each and every value in the domain.
(cosx)^2-(sinx)^2
The domain is, but the range need not be.
integration of (sinx)^1/2 is not possible.so integration of root sinx is impossible
the domain is when the denominator of the problem is set to zero... but i am not sure how to find the range
x = the domain y = the co-domain and range is the output or something e_e
2sinx - sin3x = 0 2sinx - 3sinx + 4sin3x = 0 4sin3x - sinx = 0 sinx(4sin2x - 1) = 0 sinx*(2sinx - 1)(2sinx + 1) = 0 so sinx = 0 or sinx = -1/2 or sinx = 1/2 It is not possible to go any further since the domain for x is not defined.
The domain and range are the x and y coordinates of the dot, respectively.
The domain is any subset of the real numbers that you choose, The range is the set of all values that the points in the domain are mapped to.
Describe how to find the domain and range of a relation given by a set of ordered pairs.
Use the function to find the image of each point in the domain. The set of values that you get will be the range. If the function is well behaved, you will not have to try each and every value in the domain.
The domain of the function 1/2x is {0, 2, 4}. What is the range of the function?
You need to know the domain in order to find the range.
The range of a function is the set of all of the possible values that it can take on as an output value. You find the range by inspecting the function and seeing first what the domain is, and then what the range would be for that domain. The domain, then, is the set of all of the possible values that it can take on as an input value.
the domain is all real numbers and the range is all real numbers the domain is all real numbers and the range is all real numbers
i dont know, but you can find it at purplemath.com