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Cos (aX) = 1 + bX, give value of X in terms of a and b.Practical Problem at site: An arc shape insert- plate of which R was 1250 and D was 625mm and thus S = 2618 (chord length (L)= 2165), has been damaged and flattered.

And site staff gives feedback that it is now D = 525 instead of 625 and Chord length =2280.but this all not match in a geometrical figure. One dimension is wrong. If we consider D= 525 is correct then what is new radius. S=2618 will remain unchanged. Hence if S and D is given what is new R.

By trigonometry and geometrically this relation will arrive like this

S = R . Theta ---------- Equation no. 1

where R is radius of arc and Theta is angle in radians of arc ends at centre and S is length of arc.

second relation if distance of arc centre to chord centre is = D, then

Cos (Theta/2) = (R - D)/R -------------Equation no 2

Simplifying both relation,

Cos (S/2R) = (R-D)/R

Here equation is with one unknown, because S and D is known variables. Only R is to find out.

In Simple form it can be written to solve further this equation is

Cos (aX) = 1 + bX, give value of X in terms of a and b. Please help to solve this simple Equation

R

L/2

D

Theta

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