Suppose the first term is a, the second is a+r and the nth is a+(n-1)r.
Then the sum of the first five = 5a + 10r = 85
and the sum of the first six = 6a + 15r = 123
Solving these simultaneous equations, a = 3 and r = 7
So the first four terms are: 3, 10, 17 and 24
An arithmetic series is the sum of the terms in an arithmetic progression.
It is 58465.
Arithmetic : (First term)(last term)(act of terms)/2 Geometric : (first term)(total terms)+common ratio to the power of (1+2+...+(total terms-1))
a1=2 d=3 an=a1+(n-1)d i.e. 2,5,8,11,14,17....
This is an arithmetic series, so we use the formula S=n/2 (a+l) when n is the number of terms, a is the first number and l the last. S = 100/2 (51 + 150) =50 (201) = 10050
An arithmetic series is the sum of the terms in an arithmetic progression.
It is 58465.
An arithmetic series is the sequence of partial sums of an arithmetic sequence. That is, if A = {a, a+d, a+2d, ..., a+(n-1)d, ... } then the terms of the arithmetic series, S(n), are the sums of the first n terms and S(n) = n/2*[2a + (n-1)d]. Arithmetic series can never converge.A geometric series is the sequence of partial sums of a geometric sequence. That is, if G = {a, ar, ar^2, ..., ar^(n-1), ... } then the terms of the geometric series, T(n), are the sums of the first n terms and T(n) = a*(1 - r^n)/(1 - r). If |r| < 1 then T(n) tends to 1/(1 - r) as n tends to infinity.
The sequence is arithmetic if the difference between every two consecutive terms is always the same.
Arithmetic : (First term)(last term)(act of terms)/2 Geometric : (first term)(total terms)+common ratio to the power of (1+2+...+(total terms-1))
a1=2 d=3 an=a1+(n-1)d i.e. 2,5,8,11,14,17....
-5 19 43 67 ...This is an arithmetic sequence because each term differs from the preceding term by a common difference, 24.In order to find the sum of the first 25 terms of the series constructed from the given arithmetic sequence, we need to use the formulaSn = [2t1 + (n - 1)d] (substitute -5 for t1, 25 for n, and 24 for d)S25 = [2(-5) + (25 - 1)24]S25 = -10 + 242S25 = 566Thus, the sum of the first 25 terms of an arithmetic series is 566.
This is an arithmetic series, so we use the formula S=n/2 (a+l) when n is the number of terms, a is the first number and l the last. S = 100/2 (51 + 150) =50 (201) = 10050
RAMANUJANRAMANUJAN
49
The series given is an arithmetic progression consisting of 5 terms with a common difference of 5 and first term 5 → sum{n} = (n/2)(2×5 + (n - 1)×5) = n(5n + 5)/2 = 5n(n + 1)/2 As no terms have been given beyond the 5th term, and the series is not stated to be an arithmetic progression, the above formula only holds for n = 1, 2, ..., 5.
The arithmetic mean is an average arrived at by adding all the terms together and then dividing by the number of terms.