6x and 5y
100 divided by 4 is 25.
A number subtracted from 17 gives the quotient of 48 and -8. Find the number.
Divide
solve 6x - 9 = -3x + 36?
The quotient of a number and 14 is 8. Find the number.
Dividend: 6x^3+29x^2-40x-42 Divisor: 6x+5 Quotient: x^2+4x-10 Remainder: 8
Dividend: 6x^3 +29^2 -40x -42 Divisor: 6x +5 Quotient: x^2 +4x -10 Remainder: 8
6x3+29x2-40x-42 divided by 6x+5 Quotient: x2+4x-10 Remainder: 8
6x/23
The "quotient" of two numbers is the result of a multiplication sum. Therefore, if 6x = -12, then x = -2.
x3+3x2+6x+1 divided by x+1 Quotient: x2+2x+4 Remaider: -3
6x3+29x2-40x-42 divided by 6x+5 is x2+4x-10 remainder 8 or as x2+4x-10+8/(6x+5) If the answer is correct then the quotient multiplied by the divisor should be the same as the dividend:- (6x+5)*(x2+4x-10) + (6x+5)*8/(6x+5) Multiply term by term with (6x+5):- 6x3+5x2+24x2+20x-60x-50+8 Collect like terms:- 6x3+29x2-40x-42 which makes the answer correct.
Use long division; at each stage:work out the multiplier of the divisor required to remove the highest power of x remaining in the dividend;put the multiplier found in step 1 as the next term in the quotient;multiply the divisor by this multiplier;subtract like normal;bring down the next term;repeat from step 1 until there are no more terms to bring down;If the result after the final subtraction and bringing down of terms is non-zero this is a remainder after the division by the divisor.(6x³ + 29x² - 40x - 42) ÷ (6x + 5) =__________________x² + 4x - 10________-------------------------6x + 5 |6x³ + 29x² - 40x - 42_________6x³ + 5x²_______________________← x²(6x + 5)_________------------_______________24x² - 40x_______________24x² +20x________________← 4x(6x + 5)_______________--------------____________________- 60x - 42____________________- 60x - 50___________← -10(6x + 5)____________________------------_____________________________8→ (6x³ + 29x² - 40x - 42) ÷ (6x + 5) = x² + 4x - 10 remainder 8= (x² + 4x - 10) + 8/(6x + 5)
100 divided by 4 is 25.
Suppose the number is x then [6x - sqrt(5)]/x = 1 so 6x - sqrt(5) = x or 5x = sqrt(5) x = sqrt(5)/5 = sqrt(5)
The quotient of twelve diminished by six times a number can be expressed mathematically as ( \frac{12 - 6x}{1} ), where ( x ) represents the unknown number. This expression shows that you first calculate six times the number, subtract that from twelve, and then find the quotient of the result. In simpler terms, it represents the value obtained when six times the number is taken away from twelve.
4x2 + 6x - 3 (with no remainder)