The general expression for the nth term of an AP is : a + (n - 1)d, where a is the first term and d is the common difference.
Putting n = 1, then T1 = 7 - 3 = 4, which is the value of a.
Then 7 - 3n = 4 + (n - 1)d : 3 - 3n = (n - 1)d : -3(n - 1) = (n - 1) d : d = -3.
The formula for the sum of the AP to the nth term is : Sn = n/2[2a + (n - 1)d]
Therefore S25 = 25/2[2x4 + (25-1)x-3] = 25/2[8+(24 x -3)] = 25/2[8-72] = 25/2 x - 64 = -800
terms whose variables are the same.
-8
Without an equality sign the given terms can't be considered to be a straight line equation.
Given: x2 + y2 - 10x + 4y + 4 = 0 First, we'll move our constants to the right: x2 + y2 - 10x + 4y = -4 Then group terms with the same variables together: x2 - 10x + y2 + 4y = -4 Then complete the squares: x2 - 10x + 25 + y2 + 4y + 4 = -4 + 25 + 4 (x - 5)2 + (y + 2)2 = 25 And there we have it. This is an equation for a circle whose center point is at (5, -2), with a radius of √25, which equals 5.
1
-8
5n+2 or 5n-2. I'll assume 10n 10,20,30,40,50
That's a factor pair.
2,1,0 is th sequence of its terms
All points whose y-coordinate is twice its x-coordinate.
terms whose variables are the same.
No pairs of points are given so the question cannot be understood
They form the sphere whose center is the given point and whose radius is the given distance.
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Anfernee "Penny" Deon Hardaway.
Without an equality sign the given terms can't be considered to be a straight line equation.
They are called like terms