The general expression for the nth term of an AP is : a + (n - 1)d, where a is the first term and d is the common difference.
Putting n = 1, then T1 = 7 - 3 = 4, which is the value of a.
Then 7 - 3n = 4 + (n - 1)d : 3 - 3n = (n - 1)d : -3(n - 1) = (n - 1) d : d = -3.
The formula for the sum of the AP to the nth term is : Sn = n/2[2a + (n - 1)d]
Therefore S25 = 25/2[2x4 + (25-1)x-3] = 25/2[8+(24 x -3)] = 25/2[8-72] = 25/2 x - 64 = -800
terms whose variables are the same.
-8
Without an equality sign the given terms can't be considered to be a straight line equation.
Given: x2 + y2 - 10x + 4y + 4 = 0 First, we'll move our constants to the right: x2 + y2 - 10x + 4y = -4 Then group terms with the same variables together: x2 - 10x + y2 + 4y = -4 Then complete the squares: x2 - 10x + 25 + y2 + 4y + 4 = -4 + 25 + 4 (x - 5)2 + (y + 2)2 = 25 And there we have it. This is an equation for a circle whose center point is at (5, -2), with a radius of √25, which equals 5.
1
32, 60, 88, 116, 144
-8
5n+2 or 5n-2. I'll assume 10n 10,20,30,40,50
That's a factor pair.
2,1,0 is th sequence of its terms
All points whose y-coordinate is twice its x-coordinate.
terms whose variables are the same.
-8
No pairs of points are given so the question cannot be understood
Without an equality sign the given terms can't be considered to be a straight line equation.
They form the sphere whose center is the given point and whose radius is the given distance.
Anfernee "Penny" Deon Hardaway.