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the series of odd numbers from 1 to 99 :1 3 5 7 9.....99
SUM OF THE SERIES:
It is a geometric progression with a=1 and l=99 and common difference (d)=2.
let 99 be the nth term of the sequence
so, 99=1+(n-1)d
99=1+(n-1)2
solving this we get n =50.
SUM=(n/2)(a+l)
=(50/2)(1+99)
=(25)(100)
=2500.
Find the sum of the odd integers from 1to 99.
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What is the sum of the odd numbers from 1-99?
100
What is the sum of all odd numbers to 99?
2500
Sum first 99 odd numbers?
9801 * The sum of the first two odd numbers (1+3) is 4, or 22 * The sum of the first three odd numbers (1+3+5) is 9, or 32 * The sum of the first four odd numbers (1+3+5+7) is 16, or 42 * ...and so on So the sum of the first 99 odd numbers, using the pattern above, would be 992 or 9801.
Find two consecutive odd integers whose sum is 196?
97 and 99
The sum of three consecutive odd numbers is 99 what are the numbers?
let the number be n-1, n, n+1 then 3n=99 and so n=33 the numbers are 32, 33, 34
What is the sum of all odd numbers 1 through 99?
The sum of all odd numbers 1 through 99 is 9,801.
Find the sum of all odd numbers from 1 thro 99?
answer:2500
What is the sum of the odd numbers from 1-99?
100
What is the sum of all odd numbers to 99?
2500
What is the sum of the first 99 odd numbers?
Well, darling, the sum of the first 99 odd numbers is 9801. You see, you take the last odd number, which is 197, multiply it by the total number of odd numbers (which is 99), and divide by 2. Voila! Math magic at its finest.
What is the sum of odd numbers 1-99?
100
Sum of odd numbers between 1 to 100?
99
Sum first 99 odd numbers?
9801 * The sum of the first two odd numbers (1+3) is 4, or 22 * The sum of the first three odd numbers (1+3+5) is 9, or 32 * The sum of the first four odd numbers (1+3+5+7) is 16, or 42 * ...and so on So the sum of the first 99 odd numbers, using the pattern above, would be 992 or 9801.
What is the difference between the sum of all even numbers and odd numbers from 25 to 100?
The sum of the even numbers is (26 + 28 + ... + 100); The sum of the odd numbers is (25 + 27 + ... + 99) Their difference is: (26 + 28 + ... + 100) - (25 + 27 + ... + 99) = (26 - 25) + (28 - 27) + ... + (100 - 99) = 1 + 1 + ... + 1 There are (100 - 26) ÷ 2 + 1 = 38 terms above which are all 1; their sum is 38 x 1 = 38. So the difference of the sum of all even numbers and all odd numbers 25-100 is 38.
Find two consecutive odd integers whose sum is 196?
97 and 99
What are all of the odd numbers from 1 99 inclusive added together?
The sum of 1+ 3 + 5 + ... + 99 = 50 x (1 + 99) ÷ 2 = 2500.
Find 2 consecutive odd integers whose sum is 196?
97 + 99 = 196
