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the series of odd numbers from 1 to 99 :1 3 5 7 9.....99

SUM OF THE SERIES:

It is a geometric progression with a=1 and l=99 and common difference (d)=2.

let 99 be the nth term of the sequence

so, 99=1+(n-1)d

99=1+(n-1)2

solving this we get n =50.

SUM=(n/2)(a+l)

=(50/2)(1+99)

=(25)(100)

=2500.

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13y ago

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Find the sum of the odd integers from 1to 99.

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Riza Evangelio

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1y ago
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