400 + 500 = 900
400
2 + 4 + 6 + ... + 396 + 398 + 400 = 40200
Let the first number = xThe four consecutive numbers will be x, (x+1), (x+2), and (x+3).Add them, and set the result = to 398.eg.x + x + 1 + x + 2 + x + 3 = 3984x + 6 = 398Then use algebra to solve for x.4x = 392x=98This is the first number. The following numbers can be obtained by substituting 98 for x in the above sequence. This will give you the numbers. 98, 99, 100, and 101. You will find that if you add them together, they will equal 398.Four consecutive numbers of 398 would be divided into two groups, those before 398 and those after 398.In the first group, that is those numbers before 398 would be:394, 395, 396 and 397.In the second group, that is those numbers after 398 would be:399, 400, 401 and 402.The numbers are 98, 99, 100 and 101.
247 + 398 = 645398 - 247 = 151Therefore the two numbers which add together to make 645 and have a difference of 151 are 247 and 398.
39800
The sum of all even numbers between 0 and 398 (2-396) is 157,212. If you include 398 the sum is 158,802.
400 + 500 = 900
399, 398, 397, 396, 395
1 2 199 and 398.
400
2 + 4 + 6 + ... + 396 + 398 + 400 = 40200
398
Let the first number = xThe four consecutive numbers will be x, (x+1), (x+2), and (x+3).Add them, and set the result = to 398.eg.x + x + 1 + x + 2 + x + 3 = 3984x + 6 = 398Then use algebra to solve for x.4x = 392x=98This is the first number. The following numbers can be obtained by substituting 98 for x in the above sequence. This will give you the numbers. 98, 99, 100, and 101. You will find that if you add them together, they will equal 398.Four consecutive numbers of 398 would be divided into two groups, those before 398 and those after 398.In the first group, that is those numbers before 398 would be:394, 395, 396 and 397.In the second group, that is those numbers after 398 would be:399, 400, 401 and 402.The numbers are 98, 99, 100 and 101.
398
three hundred ninety-eight.
400