Let the number be 'm' & 'm + 2'
Hence their squares are m^2 & (m+2)^2
There sum is
m^2 + (m+2)^2 = 340
Multiply out he brackets
m^2 + m^2 + 4m + 4 = 340 .
2m^2 + 4m + 4 = 340
Divide both sides by '2'
m^2 + 2m + 2 = 170
m^2 + 2m - 168 = 0
Factor
(m - 12)(m + 14) = 0
Hence m = 12 & m+ 2 = 14 The two consecutive even numbers.
12^2 = 144
14^2 = 196
144 + 196 = 340 As required.
8
15 and 16
The difference between the squares of two consecutive integers j and j+1 is |2j+1|. There are therefore two such pairs where this quantity is 17:-9 and -88 and 9
24 and 25, which are (49-1)/2 and (49+1)/2
There are two consecutive even numbers. The numbers are 62 and 64.
The numbers are 12 and 14.
The numbers are 12 and 14.
8
The numbers are 13 and 14.
15 and 16
17 and 18
62 and 63
The numbers are 8 and 9.
6,7,8 those numbers squared are 36,49,64 which add to 149
The difference between the squares of two consecutive integers j and j+1 is |2j+1|. There are therefore two such pairs where this quantity is 17:-9 and -88 and 9
Consecutive numbers are whole numbers whose difference is 1.
24 and 25, which are (49-1)/2 and (49+1)/2