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Find x 120 140 and 40?
The answer is 41
The measure of one angle is 38 degrees less than the measure of its supplement Find the measure of each angle?
x+y=180 y= x+38 x+(x+38)= 180 2x+38=180 -38 =-38 2x = 142 x= 71 plug it in equation 71+71+38= 180 angle 1 = 71 angle 2 = 109
One number is 6 greater than another number. The sum of two numbers is 38. Find the number.?
(x+6)+x=38 2x+6=38 2x=38-6 x=32/2 x=16 Therefore the one number is 16, and the other number is (16+6) which is 22. 16+22=38
What times what equals 140?
10 times 14 or 14 times 10 = 14020 times 7 or 7 times 20 = 14028 times 5 or 5 times 28 =140.70 times 2 or 2 times 70 =140.
What is 38 divisible by?
1x38 2x19 So 38 is divisible by 1, 2, 19, 38
Find x 140 38 degrees?
Who know
What is 140 of 50?
To find this you do: 50 X 100/140. So the answer is about 35.71%.
Joannas bones make up 38 of her body weight if she weighs 140 pounds how many pounds do her bones weigh?
= 140 x 0.38 = 53.2
How do you find the prime factorization of 38?
38 2,19 2 x 19 = 38
Find x 120 140 and 40?
The answer is 41
Find x 20 50 140?
5
What is 140 percent of 140?
To find 140 percent of a number, multiply the number by 1.4. In this instance, 1.4 x 140 = 196. Therefore, 140 percent of 140 is equal to 196.
What are the multiple of 140?
1 x 140 = 1402 x 140 = 2803 x 140 = 4204 x 140 = 5605 x 140 = 7006 x 140 = 8407 x 140 = 9808 x 140 = 11209 x 140 = 126010 x 140 =1460I got x10 for the people who don't know them....
Find an equation of variation where y varies directly as x and y equals 535 when x equals 140?
y=k*x 535=k*140 k=535/140=107/28 y=(107/28)*x
How do you find 38 percent of 4250?
38% of 4250 = 0.38 x 4250 = 1615
Write the prime factorization of each number 49 38 76 60 81 132 140 87?
7 x 7 = 49 2 x 19 = 38 2 x 2 x 19 = 76 2 x 2 x 3 x 5 = 60 3 x 3 x 3 x 3 = 81 2 x 2 x 3 x 11 = 132 2 x 2 x 5 x 7 = 140 3 x 29 = 87
What percent of 140 is 28?
To find 28 percent of a number, multiply the number by 0.28. In this instance, 0.28 x 140 = 39.2. Therefore, 28 percent of 140 is equal to 39.2.
