x+y=180
y= x+38
x+(x+38)= 180
2x+38=180
-38 =-38
2x = 142
x= 71
plug it in equation
71+71+38= 180
angle 1 = 71
angle 2 = 109
Two angles are said to be supplementary if they total 180 degrees. To find an angle's supplement, subtract its measure from 180.
180 - 143 = 37 degrees
The question asks for the complement of (the supplement of (80 degrees) ). We have to find the supplement of 80 first, and then find the complement of the supplement. The supplement of an angle is (180 - the angle). The complement of an angle is (90 - the angle). The supplement of 80 degrees is (180 - 80) = 100 degrees. The complement of that supplement is (90 - 100) = -10 degrees.
Suppose the measure of the angle is x then its supplement is 180 - x x = 180 - x + 30 = 210 - x 2x = 210 => x = 105 degrees (supplementary angle = 75)
Angle=54oComplement: 90-54=36oSupplement: 180-54=126o
The angles are: 43.75 degrees and 136.25 degrees
40-degrees 140-degrees
148
60 degrees and 120 degrees
Two angles are said to be supplementary if they total 180 degrees. To find an angle's supplement, subtract its measure from 180.
135 degree
two-thirds of an angle is 30degree more than its supplemant. find the angle
It is 180 -64 = 116 and 64 plus 116 = a supplementary angle of 180 degrees
180 - 143 = 37 degrees
the supplement of an 82 degrees angle would be 98 degrees. To find the supplement of an angle, take the degrees of the angle you were given and subtract it from 180.
The angles are: 150+30 = 180 degrees
The question asks for the complement of (the supplement of (80 degrees) ). We have to find the supplement of 80 first, and then find the complement of the supplement. The supplement of an angle is (180 - the angle). The complement of an angle is (90 - the angle). The supplement of 80 degrees is (180 - 80) = 100 degrees. The complement of that supplement is (90 - 100) = -10 degrees.