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That means you must take the derivative of the derivative. In this case, you must use the product rule.
y = 6x sin x
y'= 6[x (sin x)' + (x)' sin x]
= 6[x cos x + sin x]
y'' = 6[x (cos x)' + (x)' cos x + cos x]
= 6[x (-sin x) + cos x + cos x]
= 6[-x sin x + 2 cos x]
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