You can solve this by doing 9!-(!-means factorial) 9!=9x8x7x6x5x4x3x2x1 So the answer is 362,880 different ways.
The answer depends on which sport you are talking about. The number of players on a team differs from cricket to baseball, for example.
622,702,088 of them.
How many different arrangements can be formed on a self with space for 3 books if there are 5different books available?3 x 5 = 15 different arrangement 4 men and 3 women are to occupy a row of 7 seats, and men are to occupy the 2 end seats.In how many different orders can these 7 people be seated?7! = 5,040 different orders of seat A baseball manager has decided who his 9 starting players are to be. How many different battingorders can be he have?9! = 362,880 different batting orders
The arrangement of objects in different orders.
There is a choice of 12 for the first, leaving 11 for the second, leaving 10 for the third, and so on, leaving 4 for the last, a total of 12 × 11 × 10 × ... × 4 = 79,833,600 ways. ------------------------------------------------------ This is a mathematical "permutation" which is a selection of r items from a total of n items where the order of selection matters. It can be calculated by using the formula: nPr = n!/(n-r)! Where n! is n factorial which is calculated as n × (n-1) × (n-2) × ... 1 0! is defined to be: 0! = 1. In this case 12P9 = 12!/(12-9)! = 12!/3! = (12 × 10 × 9 × ... × 4 × 3 × 2 × 1)/(3 × 2 × 1) = 12 × 10 × 9 × ... × 4 = 79,833,600 as before.
The answer depends on which sport you are talking about. The number of players on a team differs from cricket to baseball, for example.
622,702,088 of them.
Well, essentially you're locking 2 players into line-up spots and leaving only 7 players to place into different orders. In that case, that should make for 49 different line-up possibilities.
How many different arrangements can be formed on a self with space for 3 books if there are 5different books available?3 x 5 = 15 different arrangement 4 men and 3 women are to occupy a row of 7 seats, and men are to occupy the 2 end seats.In how many different orders can these 7 people be seated?7! = 5,040 different orders of seat A baseball manager has decided who his 9 starting players are to be. How many different battingorders can be he have?9! = 362,880 different batting orders
There are eleven players in a cricket team, all players have the opportunity to bat LOOPDOP says: Answer is almost 40 million. 1x2x3x4......9x10x11 = 39 916 800 ( 11! = 39 916 800)
1*2*3*4*5*6*7*8*9*10=3628800
Baseball-reference.com keeps data on historical games and entire seasons. In these archives, you can find a team's batting order for a single game, or their most common batting order over a particular season.
Most professional baseball players use wood bats because metal bats are very easy to hit a home run with and most pros love the challenge behind wood bats. MLB rules dictate that players use wooden bats.
simple... there are two orders: the natural order and the inverted order.
An example of two organisms in the same class but different orders is a lion (order: Carnivora) and a horse (order: Perissodactyla). Both belong to the class Mammalia, but they are classified under different orders based on their biological characteristics and evolutionary history.
The arrangement of objects in different orders.
Rodents