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How many possible batting orders for 13 players?
622,702,088 of them.
For 9 baseball players how many different batting orders can yo make?
You can solve this by doing 9!-(!-means factorial) 9!=9x8x7x6x5x4x3x2x1 So the answer is 362,880 different ways.
Example of permutation?
How many different arrangements can be formed on a self with space for 3 books if there are 5different books available?3 x 5 = 15 different arrangement 4 men and 3 women are to occupy a row of 7 seats, and men are to occupy the 2 end seats.In how many different orders can these 7 people be seated?7! = 5,040 different orders of seat A baseball manager has decided who his 9 starting players are to be. How many different battingorders can be he have?9! = 362,880 different batting orders
If you toss a quarter 3 times how many different orders can heads and tails be tossed?
There are 23 possible outcomes this is found by there being 2 possibilities ( head or tails) that is done three times, that is 2X2X2= 8 possible combinations for the outcome. This is if order matters, that is h h t is different to t h h
What can you multiply to get 22?
There are infinitely many possible answers. One such is 10*2.2There are infinitely many possible answers. One such is 10*2.2There are infinitely many possible answers. One such is 10*2.2There are infinitely many possible answers. One such is 10*2.2
