Let its dimensions be a, b and c:- Surface area of the cuboid: 2*(a*b)+2*(b*c)+2*(a*c) in square units
First you need to know the size
the total surface area of a cuboid is : 2(lw+wh+hl) where l is length, w is width, and h is height.
For a cuboid (a 3D rectangle) of width W, height H and depth D, the surface area is: (WH + WD + HD) x 2.
2(lb+bh) where l=length b=breadth h=height
derivation of surface area of cuboid
Lateral surface area of a cuboid = 2 (Length + Breadth) × Height Lateral surface area of a cube = 4 × Side2
A cuboid is a 3 dimensional object and 3 measures are required for the total surface area of a cuboid.
Let its dimensions be a, b and c:- Surface area of the cuboid: 2*(a*b)+2*(b*c)+2*(a*c) in square units
yes
Make it infinitesimally small.
The surface area of a box, which is a cuboid, depends on its length, width and height. A cube is a special type of cuboid in which the length , width and height are all the same.
First you need to know the size
Volume = Height × Width × Depth Surface area=2(lw+wh+hl)
Surface area of a cuboid with sides x, y and z is 2(xy+yz+zx) So surface = 2*(1.45*1.45 + 1.45*5 + 5*1.45) = 2*16.6025 = 33.205
Surface area of cuboid = 2*[L*B + B*H + H*L] where L = length, B = breadth, and H = height
The total surface area of a cuboid with edges of length a, b and c units is 2*(ab + bc + ca) square units.