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Oh, dude, you're hitting me with some math lingo there! So, if x is acute and cos x is 0.6, we can use the Pythagorean identity to find sin x, which is 0.8. Then, to find tan x, we just divide sin x by cos x, giving us 0.8 / 0.6, which simplifies to 4/3. So, tan x is 4/3. Math can be cool, but like, let's not get too serious about it, right?
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Judy1. A cosine can be calculated as the length of the adjacent side divided by the length of the hypotenuse of a right angled triangle. The tangent measure is the length of the opposite side divided by the length of the adjacent side. As the cosx = 0.6 = 3/5 then we are dealing with a right angled triangle where the adjacent side measures 3 units and the hypotenuse 5 units - thus the opposite side measures 4 units as by Pythagoras' Theorem, 5² = 3² + 4². Then tanx = 4/3.
2. sin²x+cos²x=1.
sin² x=1-0.6²=0.64 and sin x=0.8.
tan x=sin x/cos x=0.8/0.6=8/6=4/3.
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How would you find out the sin tan and cos of right angle triangle?
sin, tan and cos can be defined as functions of an angle. But they are not functions of a triangle - whether it is a right angled triangle or not.
What is cos x tan x simplified?
A useful property in Trigonometry is: tan(x) = sin(x) / cos(x) So, cos(x) tan(x) = cos(x) [ sin(x) / cos (x)] = sin(x)
What are the sum and difference identities for the sine cosine and tangent functions?
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How do you find sin cos and tan?
sine(sin) = opp/hypcosecant(q) = hyp/oppcosine(cos) = adj/hypsecant(q) = hyp/adjtangent(tan) = opp/adjcotangent(q) = adj/opp
Limit when x goes to 0 tanx divided by x?
tan x = sin x / cos x, so:lim (tan x / x) = lim (sin x / x cos x). Since it is known that the limit of sin x / x = 1, you have lim 1 / cos x = 1 (since cos 0 = 1).tan x = sin x / cos x, so:lim (tan x / x) = lim (sin x / x cos x). Since it is known that the limit of sin x / x = 1, you have lim 1 / cos x = 1 (since cos 0 = 1).tan x = sin x / cos x, so:lim (tan x / x) = lim (sin x / x cos x). Since it is known that the limit of sin x / x = 1, you have lim 1 / cos x = 1 (since cos 0 = 1).tan x = sin x / cos x, so:lim (tan x / x) = lim (sin x / x cos x). Since it is known that the limit of sin x / x = 1, you have lim 1 / cos x = 1 (since cos 0 = 1).
