When y=4, x=8/5
y - 2 = 5 is the same as y = 7, which is a horizontal line above the x-axis at y=7.
5, of course!
x intercept = (5, 0) y intercept = (0, -2)
You zero out the variables in turn. Y = 9(0) + 5 Y = 5 ---------- 9X + 5 = 0 9X = - 5 X = - 5/9 Can use these points to graph line. ( - 5/9, 5)
If x equals a constant number, the graph will be a vertical line. For example, the graph of x = 5 would be a vertical line that goes through the point (5,0). x equals 5 on every point along this lines.
0 5 /--------------/-----•------/
The graph of x=5 is a vertical line on a set of coordinate axes that intercepts the x-axis at 5. Its slope is undefined.
The graph of x=5 would simply be a vertical line that passes through the x-intercept of 5. Since x=5, any single point on the graph would have the x coordinate of 5, because no matter what, x=5. This is why It is a vertical line through (5,0).
It is a horizontal line 5 units above the x-axis.
You didn't show us the following.
It's equal to -X + 5 = Y (1, 4) (5, 0)
x + y = 5y = -x + 5The graph is a straight line, with [ slope = -1 ], passing through the point [ y = 5 ] on the y-axis.
When y=4, x=8/5
Quadrants I, III and IV.
One simple solution is y = (x + 5/2)*(x - 2)*(x - 3/2) You can expand that into its cubic form, if you wish.
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