7 dimes = 7*10 cents = 70 cents
2 nickels = 2*5 cents = 10 cents
7 pennies = 7*1 cents = 7 cents
so the total is 87 cents.
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3 quarters, 1 dime, 3 nickels 2 quaters, 5 dimes 1 Fifty Cent Piece, 4 dimes, 2 nickels 1 Fifty Cent Piece, 1 quarter, 5 nickels
The dimes.The dimes.The dimes.The dimes.
Just a few ways include... 79 pennies. 3 quarters and 4 pennies. 7 dimes, 1 nickel, 4 pennies. 7 dimes, 9 pennies. 15 nickels, 4 pennies. 2 quarters, 2 dimes, 1 nickel, 4 pennies. 2 quarters, 2 dimes, 9 pennies. 2 quarters, 5 nickels, 4 pennies. 2 quarters, 29 pennies.
Letx = number of nickels 7x = number of dimes 7x (.10) + x (.05) = 3.75 .7x + .05x = 3.75 .75x = 3.75 x = 3.75/.75 = 5 nickels 7x = 35 dimes
To find out how many coins are worth $1.45 using only dimes and nickels, we can set up a system of equations. Let x be the number of dimes and y be the number of nickels. The value of x dimes is 10x cents, and the value of y nickels is 5y cents. We can write the equation 10x + 5y = 145 (since $1.45 is equivalent to 145 cents). To solve for the number of coins, we need to find a combination of x and y that satisfies this equation.