3 quarters, 1 dime, 3 nickels 2 quaters, 5 dimes 1 Fifty Cent Piece, 4 dimes, 2 nickels 1 Fifty Cent Piece, 1 quarter, 5 nickels
The dimes.The dimes.The dimes.The dimes.
Letx = number of nickels 7x = number of dimes 7x (.10) + x (.05) = 3.75 .7x + .05x = 3.75 .75x = 3.75 x = 3.75/.75 = 5 nickels 7x = 35 dimes
You could have fourteen dimes and one nickel or twenty-seven nickels and one dime or any of the combinations in between. This problem needs to know the number of coins.
one quarter, seven dimes and one nickel
Seven combinations that I can come up with: two dimes a nickel and three pennies all pennies two dimes and eight pennies a quarter and three pennies five nickels and three pennies three nickels one dime and three pennies two nickels one dime and eight pennies
You can use 5 dimes, 1 half dollar, 2 quarters, 10 nickels, 1 quarter 2 dimes and 1 nickle, 1 quarter 3 nickels and 1 dime. There are seven ways to make 50 cents without using pennies.
A dollar can be reached by adding coins together in the following ways, using ten coins or fewer: 1. A one-dollar coin. 2. Two half dollars. 3. One half dollar and two quarters. 4. One half dollar, one quarter, two dimes and one nickel. 5. One half dollar, one quarter, two dimes and five pennies. 6. One half dollar, one quarter, one dime and three nickels. 7. One half dollar, one quarter and five nickels. 8. One half dollar and five dimes. 9. One half dollar, four dimes and two nickels. 10. One half dollar, three dimes and four nickels. 11. One half dollar, two dimes and six nickels. 12. Four quarters. 13. Three quarters, two dimes and one nickel. 14. Three quarters, two dimes and five pennies. 15. Three quarters and five nickels. 16. Two quarters and five dimes. 17. Two quarters, four dimes and two nickels. 18. Two quarters, three dimes and four nickels. 19. Two quarters, two dimes and six nickels. 20. One quarter, seven dimes and one nickel. 21. One quarter, six dimes and three nickels. 22. Ten dimes. 23. One half dollar, one quarter, one dime, two nickels and five pennies
3 quarters, 1 dime, 3 nickels 2 quaters, 5 dimes 1 Fifty Cent Piece, 4 dimes, 2 nickels 1 Fifty Cent Piece, 1 quarter, 5 nickels
If a dime is worth 10, and a nickel is worth 5, then you only need SEVEN coins ! Six dimes and one nickel is all you need.
The dimes.The dimes.The dimes.The dimes.
Two nickels equal the value of one dime, therefore fourteen (14) nickels would equal the value of seven (7) dimes.
Letx = number of nickels 7x = number of dimes 7x (.10) + x (.05) = 3.75 .7x + .05x = 3.75 .75x = 3.75 x = 3.75/.75 = 5 nickels 7x = 35 dimes
One dollar
17/100
One dime, four nickels, and two pennies.
You could have fourteen dimes and one nickel or twenty-seven nickels and one dime or any of the combinations in between. This problem needs to know the number of coins.