Letx = number of nickels
7x = number of dimes
7x (.10) + x (.05) = 3.75
.7x + .05x = 3.75
.75x = 3.75
x = 3.75/.75 = 5 nickels
7x = 35 dimes
The dimes.The dimes.The dimes.The dimes.
3 quarters, 1 dime, 3 nickels 2 quaters, 5 dimes 1 Fifty Cent Piece, 4 dimes, 2 nickels 1 Fifty Cent Piece, 1 quarter, 5 nickels
7 dimes = 7*10 cents = 70 cents 2 nickels = 2*5 cents = 10 cents 7 pennies = 7*1 cents = 7 cents so the total is 87 cents.
To find out how many coins are worth $1.45 using only dimes and nickels, we can set up a system of equations. Let x be the number of dimes and y be the number of nickels. The value of x dimes is 10x cents, and the value of y nickels is 5y cents. We can write the equation 10x + 5y = 145 (since $1.45 is equivalent to 145 cents). To solve for the number of coins, we need to find a combination of x and y that satisfies this equation.
Seven nickels is 35 cents. A dollar is 100 cents, so the nickels are 35/100, or 0.35 of a dollar.
The dimes.The dimes.The dimes.The dimes.
Two nickels equal the value of one dime, therefore fourteen (14) nickels would equal the value of seven (7) dimes.
3 quarters, 1 dime, 3 nickels 2 quaters, 5 dimes 1 Fifty Cent Piece, 4 dimes, 2 nickels 1 Fifty Cent Piece, 1 quarter, 5 nickels
A dollar can be reached by adding coins together in the following ways, using ten coins or fewer: 1. A one-dollar coin. 2. Two half dollars. 3. One half dollar and two quarters. 4. One half dollar, one quarter, two dimes and one nickel. 5. One half dollar, one quarter, two dimes and five pennies. 6. One half dollar, one quarter, one dime and three nickels. 7. One half dollar, one quarter and five nickels. 8. One half dollar and five dimes. 9. One half dollar, four dimes and two nickels. 10. One half dollar, three dimes and four nickels. 11. One half dollar, two dimes and six nickels. 12. Four quarters. 13. Three quarters, two dimes and one nickel. 14. Three quarters, two dimes and five pennies. 15. Three quarters and five nickels. 16. Two quarters and five dimes. 17. Two quarters, four dimes and two nickels. 18. Two quarters, three dimes and four nickels. 19. Two quarters, two dimes and six nickels. 20. One quarter, seven dimes and one nickel. 21. One quarter, six dimes and three nickels. 22. Ten dimes. 23. One half dollar, one quarter, one dime, two nickels and five pennies
7 dimes = 7*10 cents = 70 cents 2 nickels = 2*5 cents = 10 cents 7 pennies = 7*1 cents = 7 cents so the total is 87 cents.
Seven combinations that I can come up with: two dimes a nickel and three pennies all pennies two dimes and eight pennies a quarter and three pennies five nickels and three pennies three nickels one dime and three pennies two nickels one dime and eight pennies
If a dime is worth 10, and a nickel is worth 5, then you only need SEVEN coins ! Six dimes and one nickel is all you need.
To find out how many coins are worth $1.45 using only dimes and nickels, we can set up a system of equations. Let x be the number of dimes and y be the number of nickels. The value of x dimes is 10x cents, and the value of y nickels is 5y cents. We can write the equation 10x + 5y = 145 (since $1.45 is equivalent to 145 cents). To solve for the number of coins, we need to find a combination of x and y that satisfies this equation.
You can use 5 dimes, 1 half dollar, 2 quarters, 10 nickels, 1 quarter 2 dimes and 1 nickle, 1 quarter 3 nickels and 1 dime. There are seven ways to make 50 cents without using pennies.
Seven nickels is 35 cents. A dollar is 100 cents, so the nickels are 35/100, or 0.35 of a dollar.
73 dimes
Actually, it is both. Seven dimes (70¢) = 70% of one dollar or 7/10 of one dollar.