There are several answers to this depending on the shape of the area.
If the area was a square it would measure 10 feet by 10 feet.
It could be a very narrow oblong measuring 100 feet by 1 foot, and so on.
Assuming Width <= Length then the width can be any positive value less than sqrt(270) feet = 16.43 feet (approx). Width = 15 ft goes with Length = 270/15 = 18 feet Width = 10 ft with Length = 270/10 = 27 ft Width = 0.0001 ft with Length = 270/0.0001 = 2700000 ft etc.
Area = Length * Width = 13 ft * 6 ft = 13*6 sq ft = 78 sq ft
if the units are already in feet, it is 8,500sq ft. multiply the length by width
Let the width be 2x and the length be x: width*length = area 2x*x = 200 sq ft 2x2 = 200 Divide both sides by 2 and then square root both sides: x = 10 Therefore: length = 10 ft and width = 20 ft
Length = 10 ft Width = 8 ft
Just multiply the length by the width to get square feet. 100x100=10,000sq ft
Depends length-25ft width-10ft length - 125ft width - 2ft length - 50ft width- 5ft
7,257 width in ft 8,542 length in ft
5 ft in Width and 16 ft in length
The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.
Length*Width = Area so Width = Area/Length = 40.64 sq ft/12.7 ft = 3.2 ft.
30 ft.
Perimeter = 2(length + width) → width = perimeter ÷ 2 - length length = 1 foot → width = 70 ft ÷ 2 - 1 ft = 34 ft; length = 2 feet → width = 70 ft ÷ 2 - 2 ft = 33 ft.
area = width x length width = area/length width = 925 sq ft/37 ft width = 25 ft
Not at all.Rectangle A:-- Length = 20-ft, Width = 10-ft.-- Area = 200 square ft-- Perimeter = 60-ftRectangle B:-- Length = 16-ft, Width = 12.5-ft-- Area = 200 square ft-- Perimeter = 57-ftRectangle C:-- Length = 40-ft, Width = 5-ft-- Area = 200 square ft-- Perimeter = 90-ftRectangle D:-- Length = 50-ft, Width = 4-ft-- Area = 200 square ft-- Perimeter = 108-ftRectangle E:-- Length = 100-ft, Width = 2-ft-- Area = 200 square ft-- Perimeter = 204-ftRectangle F:-- Length = 800-ft, Width = 3 inches-- Area = 200 square ft-- Perimeter = 1600-ft 6-in
Let the width be 1/2x+20 and the length be x: 2(width+length) = perimeter 2(1/2x+20+x) = 520 ft x+40+2x = 520 x+2x = 520-40 3x = 480 x = 160 Therefore: width = 100 ft and length = 160 ft Check: 2(100+160) = 520 ft
It is: 30 feet Check: 30+30+20+20 = 100 feet