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What is the width of a rectangle with an area of 270 sq feet?
Assuming Width <= Length then the width can be any positive value less than sqrt(270) feet = 16.43 feet (approx). Width = 15 ft goes with Length = 270/15 = 18 feet Width = 10 ft with Length = 270/10 = 27 ft Width = 0.0001 ft with Length = 270/0.0001 = 2700000 ft etc.
What is the area of a rectangle with length of 13' and width of 6'?
Area = Length * Width = 13 ft * 6 ft = 13*6 sq ft = 78 sq ft
What are the dimensions of 10ft by 8 ft?
The dimensions of a 10ft by 8ft area refer to its length and width. The 10ft measurement represents the length of the area, while the 8ft measurement represents the width. In this case, the area is rectangular, with a length of 10 feet and a width of 8 feet.
What is a lot 85 x 100 in square feet?
if the units are already in feet, it is 8,500sq ft. multiply the length by width
The width of a rectangle is half as long as the length the rectangle has an area of 200 square feet what are the length and width of the rectangle?
Let the width be 2x and the length be x: width*length = area 2x*x = 200 sq ft 2x2 = 200 Divide both sides by 2 and then square root both sides: x = 10 Therefore: length = 10 ft and width = 20 ft
How big is a 100 ft by 100 ft room?
Just multiply the length by the width to get square feet. 100x100=10,000sq ft
How big is 250 sq ft in length and width?
Depends length-25ft width-10ft length - 125ft width - 2ft length - 50ft width- 5ft
How big is an average swing set?
5 ft in Width and 16 ft in length
How big is Jennette mccurdy house?
7,257 width in ft 8,542 length in ft
What is the surface area of the roman Colosseum?
The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.The length of the Colosseum is 620 ft. The width of the Colosseum is 513 ft. Length x width = area. Do the math.
What is the width of a rectangle with an area of 300 square feet and its length is 3?
The width of the rectangle can be calculated by dividing the area by the length. In this case, the width would be 100 feet (300 sq ft ÷ 3 ft).
What is the width of a rectangular if the area is 40.64 sq ft length is 12.7 ft?
Length*Width = Area so Width = Area/Length = 40.64 sq ft/12.7 ft = 3.2 ft.
What is the length of a rectangle if the perimeter is 100 feet and the width is 20 feet?
30 ft.
What is the width of a rectangle with a perimeter of 70 feet if its length is 1 feet 2 feet?
Perimeter = 2(length + width) → width = perimeter ÷ 2 - length length = 1 foot → width = 70 ft ÷ 2 - 1 ft = 34 ft; length = 2 feet → width = 70 ft ÷ 2 - 2 ft = 33 ft.
If a room as an area of 925 square feet what is the width if the length is 37 feet?
area = width x length width = area/length width = 925 sq ft/37 ft width = 25 ft
If 2 rectangles have the same area must they have the same perimeter?
Not at all.Rectangle A:-- Length = 20-ft, Width = 10-ft.-- Area = 200 square ft-- Perimeter = 60-ftRectangle B:-- Length = 16-ft, Width = 12.5-ft-- Area = 200 square ft-- Perimeter = 57-ftRectangle C:-- Length = 40-ft, Width = 5-ft-- Area = 200 square ft-- Perimeter = 90-ftRectangle D:-- Length = 50-ft, Width = 4-ft-- Area = 200 square ft-- Perimeter = 108-ftRectangle E:-- Length = 100-ft, Width = 2-ft-- Area = 200 square ft-- Perimeter = 204-ftRectangle F:-- Length = 800-ft, Width = 3 inches-- Area = 200 square ft-- Perimeter = 1600-ft 6-in
The top floor is rectangular and has perimeter 520 ft The width of top floor measres 20 ft more than one-half its length What are the dimensions of the top floor?
Let the width be 1/2x+20 and the length be x: 2(width+length) = perimeter 2(1/2x+20+x) = 520 ft x+40+2x = 520 x+2x = 520-40 3x = 480 x = 160 Therefore: width = 100 ft and length = 160 ft Check: 2(100+160) = 520 ft
