Area = Length * Width = 13 ft * 6 ft = 13*6 sq ft = 78 sq ft
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
If the area is 117 square meters and the width is 9 meters we can find the length by dividing: 117 / 9 = 13 The length is 13 meters
Area of a rectangle = length X height = 3*13 = 39 square feet.
Perimeter: just add the sides. 13+13+7+7= 40 Area: multiply the length by the width. 13x7= 91 Make sure to put the unit of measurement too! :) (oh, by the way, I'm guessing this is a rectangle)
To find the square footage of a room, you simply multiply the length by the width. In this case, a room that is 13 feet long and 19 feet wide would have a square footage of 247 square feet (13 x 19 = 247). This calculation is based on the formula for the area of a rectangle, where Area = Length x Width.
To get the area of a rectangle, the formula is length times width, so 13x6= 78 inches.
156
The area of rectangle is : 78.0
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
13I2 square inches.
If the area is 117 square meters and the width is 9 meters we can find the length by dividing: 117 / 9 = 13 The length is 13 meters
4 x 13 = 52cm2 Length x Width = Area
Width is 5.
4.5 yardsArea = Length * Width58.5 = 13 * w58.5/13 = 13w/1358.5/13 = w4.5 = wthus, width = 4.5 yards
A = wl91 = w1391/13 = w13/13w = 7m
Length= 3 + 2W Area [65]= L x W You can use guess and check put plugging in 1,2,3... etc to do this one. I got Length= 13 and Width= 5 5 x 13 = 65
Its width is 13 feet and 13*19 = 247 square feet