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There are a couple of ways for a woman to get ride of a 5 o'clock shadow. You can shave in angles, get permanent hair removal, or use foundation to cover the shadow.

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9y ago
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Q: How can a woman get rid of a 5 o'clock shadow?
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Thomas happened to notice that 4 oclock pm on his uncles farm a fence post that was 5 ft tall cast a 2 foot shadow he also noticed that a nearby tree cast a 10 foot shadow how tall is the tree?

25 feet tall This is in effect asking about similar triangles, the bases of which are the shadows and the (perpendicular) heights are the heights of the objects. Therefore, using the ratio of the two triangles (calculated from the "shadow" sides) the height of the tree can be determined. The ratio of the shadows of the post to tree is: 2ft : 10ft = 1:5 So the height of the tree is five times the height of the post. Thus: Height_of_tree = 5 x 5ft = 25 ft


A vertical pole 5 feet long casts a shadow of 2 feet if at the same time a nearby tree casts a shadow of 10 feet how tall is the tree?

The tree is 25 feet tall. A 5 foot pole cast a 2 foot shadow. This means that the sun angle causes the shadow to be 2/5 the length of the object casting it. The tree's shadow is 10 feet tall. Multiply 10 feet by 5/2 (inverting the fraction because we're going the other way) and we get 25 feet.


Rules to 5 minutes to get rid of it?

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On a sunny day a 5-foot red kangaroo casts a shadow that is 7 feet long The shadow of a nearby eucalyptus tree is 35 feet long Write and solve a proportion to find the height of the tree?

the answer is 25.


At a certain time of the day the shadow of a 5 foot tall boy is 8 feet long the shadow of a tree at this time is 28 foot long how tall is the tree?

They both have the same tangent ratio. Let x be the height of the tree: x/28 = 5/8 Multiply both sides by 28: x = 140/8 x = 17.5 feet