(8*8*8)+(8*8*8)-8-8-8=1000
888 + 88 + 8 + 8 + 8 = 1000
First of all line all your eights' up. Heres the answer: 888+88+8+8+8= 1000!
There are 0 eight's in three, but there are two and two third threes in eight. Hope this helps :)
-- Split the 8s up into two groups of four. -- Do any kind of arithmetic or algebra you want to with one group of four 8s. -- Do exactly the same thing with the other group of four 8s, and give it a negative sign. -- Add the two groups of 8s. The sum is zero.
(8*8*8)+(8*8*8)-8-8-8=1000
888 + 88 + 8 + 8 + 8 = 1000
First of all line all your eights' up. Heres the answer: 888+88+8+8+8= 1000!
There are 0 eight's in three, but there are two and two third threes in eight. Hope this helps :)
If you are counting the digit eight then there is 22 of them
-- Split the 8s up into two groups of four. -- Do any kind of arithmetic or algebra you want to with one group of four 8s. -- Do exactly the same thing with the other group of four 8s, and give it a negative sign. -- Add the two groups of 8s. The sum is zero.
888 + 88 + 8 + 8 + 8 = 1000
I only need seven 8's to get to 100 88 + 88/8 + 8/8 = 100 888/8 - 88/8 = 100
In Hong Kong, the only number would be 8s. In Hong Kong numerology "8" = money so a phone number with all 8s = megamoney
eight and a half 8's go into 68 (8.5)
p = 4s a = s2 2p = a - 48 8s = a - 48 8s = s2 - 48 -s2 + 8s + 48 = 0 s2 - 8s - 48 = 0 (s - 12)(s - 4) = 0 s = 12 or 4
A decimal number is simply a way of representing a number in such a way that the place value of each digit is ten times that of the digit to its right. A decimal representation does not require a decimal point. So the required decimal representation is 8s, as in the question.