(8*8*8)+(8*8*8)-8-8-8=1000
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Yes, 888+88+8+8+8=1000
The sum 9 + 99 + 999 + 9999 + 99 999 + .... where the last number to be added consists of nine digits of 9 becomes: (10 – 1) + (100 – 1) + (1000 – 1) + (10 000 – 1) + ... where the last multiple of 10 has nine zeros. There are nine pairs of brackets altogether. Add the multiples of 10 first and then subtract 9: The digit 1 appears 9 times in the final answer.
no
2x4x3 is 24+1 is 25, x4 is 100. 2x3 is 6+4 is 10. 10*100 is 1000. That is one way. All ways require using the numbers more than once
87400 combinations