1 plus 2 plus 3 plus 4 equal 10. 10 times 5 equals 50.
To find the 9 odd numbers whose sum is 50 from 1 to 50, we can first calculate the sum of all odd numbers from 1 to 50, which is (50^2)/2 = 625. Next, we subtract the sum of the first 9 odd numbers (1+3+5+7+9+11+13+15+17 = 81) from the total sum, resulting in 625 - 81 = 544. Therefore, the 9 odd numbers whose sum is 50 from 1 to 50 are 19, 21, 23, 25, 27, 29, 31, 33, and 36.
Just calculate the cube of 0, the cube of 1, the cube of 2, etc.
Ans: 50000 Solution : From 1 to 100 : 50 numbers can be divided by 2. Therefore for 100000, TOTAL numbers that can be divided by 2 = (100000/100)*50 = 50000 Regards, DINESH Ans: 50000 Solution 1: From 1 to 100 : 50 numbers can be divided by 2. Therefore, TOTAL numbers between 1 to 100000 that can be divided by 2 = (100000/100)*50 = 50000 So, for 100 to 100000 it is 50000 - 50 = 49950 Solution 2: (100000 / 2 ) - ( 100 / 2 ) = 49950 Dina
100
There are many sets of numbers with an average of 50.Two numbers with an average of 50 is 49 and 51.
Chances of not getting odd or prime number from 1 to 50= Chances of getting an even composite number from 1 to 50= Number of even composite numbers from 1 to 50/Total numbers from 1 to 50 = 24/50 or 48%Chances of not getting odd or prime number from 1 to 50= Chances of getting an even composite number from 1 to 50= Number of even composite numbers from 1 to 50/Total numbers from 1 to 50 = 24/50 or 48%Chances of not getting odd or prime number from 1 to 50= Chances of getting an even composite number from 1 to 50= Number of even composite numbers from 1 to 50/Total numbers from 1 to 50 = 24/50 or 48%Chances of not getting odd or prime number from 1 to 50= Chances of getting an even composite number from 1 to 50= Number of even composite numbers from 1 to 50/Total numbers from 1 to 50 = 24/50 or 48%
There is a total of 48 numbers between one and 50 that are multiples of four.
1, 2, 5, 10, 25, 50 | 1 x 50, 2 x 25, 5 x 10.
1,2,3,5,7,11,13,17,19,23,29,31,37,39,41,43,and 49
5 odd numbers CAN'T add up to an even number like 50
To find the 9 odd numbers whose sum is 50 from 1 to 50, we can first calculate the sum of all odd numbers from 1 to 50, which is (50^2)/2 = 625. Next, we subtract the sum of the first 9 odd numbers (1+3+5+7+9+11+13+15+17 = 81) from the total sum, resulting in 625 - 81 = 544. Therefore, the 9 odd numbers whose sum is 50 from 1 to 50 are 19, 21, 23, 25, 27, 29, 31, 33, and 36.
#include int main(){int i,total=0;for(i=1;i
The probabiliy of selecting odd or prime numbers from 1 to 50. First find out the probability of selecting odd numbers : 25/50 is 1/2. Lets find out the probability of selecting prime numbers: 15 / 50 . so, total is 40/ 50 is 0.82.
Your score or amount divided by the total number and multiplied by 100 So if you got 35/50 on your maths test, divide 35 by 50 and multiply the answer by 100. 35/50*100=70%
101 to 199 give 50 odd numbers. Their sum is 7,500.[I'm not too certain that the question meant 'the average total'? But, the odd numbers average total would be 7,500 ÷ 50 = 150]
Just calculate the cube of 0, the cube of 1, the cube of 2, etc.
100,000+20,000+3,000+400+50+6=