#include
int main()
{
int i,total=0;
for(i=1;i<=50;++i) total+=i;
printf("Total: %d\n",total);
return 0;
}
The sum of the first 50 whole numbers is 1,225.
The sum of the first 50 even numbers is 2,550.
The sum of the first 50 odd numbers is 2,500.
The sum of the first 50 natural numbers is 1,251.
the sum of first 50 consecutive odd numbers is 9801
The sum of the first 50 counting numbers, excluding zero, is 1,251.
The sum of the first 50 odd numbers is 2,500. This can be calculated using the formula for the sum of the first ( n ) odd numbers, which is ( n^2 ). For ( n = 50 ), the sum equals ( 50^2 = 2,500 ).
sum of n natural number is n(n+1)/2 first 50 number sum is 50(50+1)/2 = 1275
10 for t = 1 to 50 20 input a 30 c = c + a 40 next t 50 print c
of all the things i got is 2550
2500
To find the 9 odd numbers whose sum is 50 from 1 to 50, we can first calculate the sum of all odd numbers from 1 to 50, which is (50^2)/2 = 625. Next, we subtract the sum of the first 9 odd numbers (1+3+5+7+9+11+13+15+17 = 81) from the total sum, resulting in 625 - 81 = 544. Therefore, the 9 odd numbers whose sum is 50 from 1 to 50 are 19, 21, 23, 25, 27, 29, 31, 33, and 36.