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If tansqtheta plus 5tantheta0 find the value of tantheta plus cottheta?
tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2
What is cos theta multiplied by csc theta?
It is cotangent(theta).
What is cosine squared theta equal to'?
Cosine squared theta = 1 + Sine squared theta
Express csc theta in terms of cot theta theta is in quadrant 3?
It is -sqrt(1 + cot^2 theta)
Letter after theta?
The letter after Theta is Iota.
How can you find the theta if the given is just the coefficient friction and the mass?
If by theta you mean the angle at the base of slope on which is the body laying, and you want to calculate minimal theta for which the blocks starts to slide: Let's first calculate: weight: Q = mg force normal to the slope: N = Q cos theta = mg cos theta force tangent to the slope: F = Q sin theta = mg sin theta force of friction: T = fN = fmg cos theta, where f is coefficient of friction The body will start to move downwards, when T = F, or: fmg cos theta = mg sin theta which after simplyfying becomes: f cos theta = sin theta, f = sin theta / cos theta f = tan theta Therefore, theta = arc tan f As you see, the angle only depends on friction coefficient f. (If that's not a problem you asked to be solved, edit your question please to precisely state what needs to be calculated)
If a curve with a radius of 60 m is properly banked for a car traveling 60 kmh what must be the coefficient of static friction for a car not to skid when travelling at 90 kmh?
To prevent skidding at 90 km/h, the car would need a coefficient of static friction of at least 0.25. This value can be calculated using the formula: coefficient of friction = tan(theta), where theta is the angle of banking. Given the curve radius, speed, and the formula, we can determine the necessary value for the coefficient of friction.
A 5.0 kg wooden block is placed on an adjustable wooden inclined plane. What is the angle of incline above which the block will start to slide down the plane .57?
The angle of incline at which the block will start to slide down is when the component of the gravitational force parallel to the plane equals the maximum static friction force. This angle can be calculated using the formula: θ = tan^(-1)(μ_s), where μ_s is the coefficient of static friction between the block and the plane. Given the angle is 0.57, one can find the coefficient of static friction using this formula.
Can you predict the angle at which an inclined plane can be inclined if an object is placed on it and all you know is the coefficient of friction between the object and the surface of the plane?
Yes, we can predict the angle at which an inclined plane can be inclined by using the coefficient of friction. The angle at which an object placed on the inclined plane will start sliding is called the angle of repose. It can be calculated using the equation: Angle of repose = arctan(coefficient of friction).
How to find Force of friction around circle?
T1/T2=e^(mu*theta)where T1/2 are the tensions in the circlemu is the coefficient of frictiontheta is the angle of the circle in contact with the rope.
How much work does Paul's force do during a displacement of the crate that is 12.0 m?
The work done by Paul's force is given by the formula Work = Force x Distance x cos(theta), where theta is the angle between the force and the direction of displacement. If the force is in the same direction as the displacement, then theta = 0 and the work done is simply Force x Distance. If the angle is not given, assuming theta = 0, the work done is the force times the distance.
If you have to do 2.2 of work to push a 78- trunk 3.1 along a slope inclined upward at 22 pushing parallel to the slope What is the coefficient of friction between trunk and slope?
The work done to move the trunk up the slope is equal to the change in potential energy. The work can be calculated using the formula W = F * d * cos(theta), where W = 2.2 J, F is the force needed (78 N), d is the distance (3.1 m), and theta is the angle of inclination (22 degrees). By rearranging the formula, you can solve for the coefficient of friction, which is μ = W / (m * g * d * cos(theta)), where μ is the coefficient of friction, m is the mass (78 kg), and g is the acceleration due to gravity (9.8 m/s^2).
A solid homogenous sphere rolls without slipping down a plane that makes an angle of 30 degree with the horizontal find the linear acceleration of the sphere and the minimum coefficient of friction?
The linear acceleration of the sphere down the incline can be calculated using the formula (a = g \sin(\theta)), where (g) is the acceleration due to gravity (9.8 m/s(^2)) and (\theta) is the angle of the incline. Substituting the values, we get (a = 9.8 \times \sin(30) = 4.9 , \text{m/s}^2). The minimum coefficient of friction required to prevent slipping can be calculated using the formula (\mu_{\text{min}} = \tan(\theta)), where (\mu_{\text{min}}) is the minimum coefficient of static friction. Substituting the values, we get (\mu_{\text{min}} = \tan(30) \approx 0.577).
How much work is done if the sled moves 10 horizontally?
The work done on the sled is given by the formula: work = force x distance x cos(theta), where theta is the angle between the force and the direction of motion. If the force is applied horizontally and moves the sled horizontally, the angle theta is 0, and the work done is simply force x distance.
What is the maximum acceleration a car can undergo if the coefficient of static friction between the tires and the ground is 0.78?
The maximum acceleration a car can undergo is equal to the coefficient of static friction multiplied by the acceleration due to gravity. So, in this case, it would be 0.78 times 9.81 m/s^2, which equals 7.66 m/s^2.
How do you measure friction when not knowing the normal force?
Well you can always work out the normal force... if the object is on a horizontal surface... The normal force is equal to the mass of the object × gravity (9.81). If the object is on an incline, you have to get the component of weight which is equivalent to the Normal, in most cases it is Normal = mass × gravity × cos(theta), theta being the angle of inclination.
What is the work done by the force, ( f ), to move the pendulum from ( theta 0 ) to ( theta theta0 )?
The work done by the force, ( f ), to move the pendulum from ( theta 0 ) to ( theta theta0 ) is equal to the change in potential energy of the pendulum.
