Oh, dude, it's like basic math, right? So, if you take 8 times 8, you get 64. Then, if you add 1 to that, you get 65. Finally, just add three zeros to the end, and bam, you've got 1000. Easy peasy lemon squeezy!
(8*8*8)+(8*8*8)-8-8-8=1000
Yes, 888+88+8+8+8=1000
8 goes into 1000 125 times
888, 88, 8, 8, 8.
Given: Total sum = 1000 To find: Terms (using 8) that adds up to 1000 =? Solution: The given question has the following conditions: Using number 8 only 8 times Addition of terms only Step 1: Write number 8 for 8 times which is equal to 100 => 8 8 8 8 8 8 8 8 = 1000 Step 2: Consider the 3 digit number made of 8 => 3 digit number = 888 => 8 used 3 times Step 3: Consider the 2 digit number made of 8 => 2 digit number = 88 => 8 used 2 times Step 4: Consider 1 digit number made of 8 => 1 digit number= 8 + 8 + 8 => 8 used 3 times To sum up: => 888 + 88 + 8 + 8 + 8 = 1000 Hence by adding up all terms using 8 we get 1000.
888 + 88 + 8 + 8 + 8 = 1000
The answer depends on what mathematical operations are allowed. One possible solution is 888/.888 = 1000.
Multiply 8 by 125.
(8*8*8)+(8*8*8)-8-8-8=1000
Yes, 888+88+8+8+8=1000
It is: 8 times 125 = 1000
888, 88, 8, 8, 8.
8 goes into 1000 125 times
8 8 8 88 888 1000
Given: Total sum = 1000 To find: Terms (using 8) that adds up to 1000 =? Solution: The given question has the following conditions: Using number 8 only 8 times Addition of terms only Step 1: Write number 8 for 8 times which is equal to 100 => 8 8 8 8 8 8 8 8 = 1000 Step 2: Consider the 3 digit number made of 8 => 3 digit number = 888 => 8 used 3 times Step 3: Consider the 2 digit number made of 8 => 2 digit number = 88 => 8 used 2 times Step 4: Consider 1 digit number made of 8 => 1 digit number= 8 + 8 + 8 => 8 used 3 times To sum up: => 888 + 88 + 8 + 8 + 8 = 1000 Hence by adding up all terms using 8 we get 1000.
888 + 88 + 8 + 8 + 8 = 1000
888 + 88 + 8 + 8 + 8 = 1000