i'll take a stab at it, though i'm a java person..
#include<stdio.h>
main() {
for (int i = 1; i<9;){ printf(i); i*=-1; if(i<0) i-=2;
else
i+=2;
}
}
5/(√3 - 1)= 5(√3 + 1)/(√3 - 1)(√3 + 1)= (5√3 + 5)/[(√3)2 - 12)= (5√3 + 5)/(3 - 1)= 5√3 + 5)/2= 5√3/2 + 1/2
31/5 = 16/5 so 16 fifths in it.
5 / (1/3) = 5 x (3/1) = 155 / (1/3) = 5 x (3/1) = 155 / (1/3) = 5 x (3/1) = 155 / (1/3) = 5 x (3/1) = 15
include<stdio.h> #include<conio.h> main() { int i; /* looping variable */ for(i=1;i<=100;i++) /* goes from 1 to 100 */ { if((i % 2 == 0) && (i % 3 != 0) && (i % 5 != 0)) /* checks all three conditions */ { printf("%d ",i); /* note the space after 'd' */ } } printf("\nEnd of Program"); /* End */ getch(); }
1 3/5= 8/5 How You Do It 1. 5 x 1 = 5 2. 5 + 3 = 8 3. Keep the denominator the same.
System.out.println("2, 3, 5, 7"); There are so few you dont need to calculate it
EXAMPLE 1 PRINT 1+3+5+7 EXAMPLE 2 FOR num% = 1 TO 7 STEP 2 total%=total%+num% NEXT PRINT total%
Any of the following are snippets of code providing some ways of doing it: printf("1 2 3 4 5 6"); write(0, "1 2 3 4 5 6", 11); puts("1 2 3 4 5 6"); for (i = 0; i++ < 5; printf("%d ", i); printf("%d", i); for (i = 0; ++i < 6; putchar(' ')) putchar('0' + i); putchar('0' + i);
Oh, dude, finding Hobo 1 to 5 codes is like searching for buried treasure in a landfill. You can try scouring the internet for forums or cheat code websites, but honestly, who has time for that? Just play the game and embrace the chaos, man.
12345 1234 123 12 1
3400 (LA1) Code E Engine: 1-2-3-4-5-6; 3800 (L36) Code K Engine: 1-6-5-4-3-2; 3800 (L67) Code 1 Supercharged Engine: 1-6-5-4-3-2.....
3400 (LA1) Code E Engine: 1-2-3-4-5-6; 3800 (L36) Code K Engine: 1-6-5-4-3-2; 3800 (L67) Code 1 Supercharged Engine: 1-6-5-4-3-2.....
1 - 2 - 3 - 4 - 5
you putt the code in 5 3 2 1 2 1 3
3-3...3-3....3-3....3-4.....5-3.....5-3....
REMPATTERNS (not necessary) CLS FOR I = 1 TO 5 STEP +1 FOR J = 1 TO I STEP+1 PRINT J NEXT J PRINT NEXT I END Hope you find this helpful :)
QBASIC CODE/START... ==== ...QBASIC CODE/END.