r+r+r+r+r=10
therefore, r must equal two
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If: 2p+5r = q Then: p = (q-5r)/2
First, translate it into an algebraic equation:4 + 5r = -11Then we subtract 4 from both sides:4 + 5r - 4 = -11 - 4Now we can simplify our numbers together:(4 - 4) + 5r = -11 - 40 + 5r = -155r = -15Now we divide both sides by 5:(5r / 5) = (-15 / 5)r = -3
13r +10 =5r-46 13r-5r=-46-10 8r=-56 8r/8=-56/8 r=-7 use the system of letter one side and numbers one side. also when you move the numeral to the left after the equal sign you need to change the sign if it's positive make it negative, if negative make it positive.
1)5r+7=13+2r+3r 2)5r+7=13+5r 3)5r's cancel 7=13 4)Subtract thirteen on both sides 7 =13 -13 -13 5)Answer is no solution because -6 doesn't equal to 0. -6=0 NO SOLUTION!!! Have fun with math!
5r + r = 6r