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How is the Fibonacci sequence defined?
the sequence of numbers when the first 2 numerals are 0 then 1 followed by the addition of the past t2 numbers example-0,1,1,2,3,5,8,13 etc
How can you prove by using Kepler's Law that the linear velocity of a planet varies as the square root of the mean distance from the Sun?
It doesn't. It varies inversely as that square root.Here's how I did it:T = time for a planet's revolutionR = mean distance from the sunK = some konstant, any konstantV = planet's linear speedKepler's 3rd law: T2/R3 = K . . . . . T2 = K R3But T = orbital circumference/V , so (2 pi R/V)2 = K R3 , and (2 pi/V)2 = K RDivide ' 1 ' by each side:(V/2 pi)2 = 1/K R or V2 = 1/K R (new konstant)V = K sqrt( 1/R )qed
What is the answer to the math worksheet Did You Hear About?
t2 + 3t - 10
How do you work out triangular numbers?
The triangular numbers are 1, 3, 6, 10, 15, ... and are calculated as: t1 = 1 t2 = 1 + 2 t3 = 1 + 2 + 3 tn = 1 + 2 + ... + n The formula for the sum tn = 1 + 2 + ... + n is: tn = n(n+1)/2
What numbers are missing from this pattern 36 37 39 42 72 81 91 102?
46, 51, 57, 64 ----------------------------------------------------------------------------------------- What numbers would you like to be missing? Whatever numbers you specify, I can give you a formula for the general term of the pattern so that the numbers already specified, and the wanted numbers appear for the terms 1, 2, ..., n However, the pattern given looks like it is: 36, 37, 39, 42, w, x, y, z, 72, 81, 91, 102, for which the simplest formula for the general term is t{n} = (x² -x + 72)/2 which means the missing terms t{5-8} are: w = t5 = (5² - 5 + 72)/2 = 46 x = t6 = (6² - 6 + 72)/2 = 51 y = t7 = (7² - 7 + 72)/2 = 57 z = t8 = (8² -8 + 72)/2 = 64 The formula is derived from the fact that the difference between one term and the next is one more than the difference between the previous term and that term: t2 = t1 + 1 t3 = t2 + 2 = t2 + 1 + 1 t4 = t2 + 3 = t2 + 2 + 1 → t5 = t4 + 3 + 1 = t4 + 4 = 42 + 4 = 46 → t6 = t5 + 4 + 1 = t5 + 5 = 46 + 5 = 51 → t7 = t6 + 5 + 1 = t6 + 6 = 51 + 6 = 57 → t8 = t7 + 6 + 1 = t7 + 7 = 57 + 7 = 64 → t9 = t8 + 7 + 1 = t8 + 8 = 64 + 8 = 72 and the sequence continues.
What is the formula for the series-parallel connection?
/t=/t1=/t2=/t3... vt=v1+v2+v3... rt=r1+r2+r3... series formula....
Compared to the period of satellites in orbit close to the Earth the period of satellites in orbit far from the Earth is A the same B longer C shorter D not enough information?
B( T2/R3 = constant )
How is the Fibonacci sequence defined?
the sequence of numbers when the first 2 numerals are 0 then 1 followed by the addition of the past t2 numbers example-0,1,1,2,3,5,8,13 etc
What pattern does the planets orbit the sun in?
Planets orbit the sun in proportion to the radius of their orbit. The Radius Cubed is proportional to the Time Squared. R3 = kT2 Therefore, R3/T2 = k (k will always be the same number)
What does the term Tn mean in maths?
The answer depends on the context. It could refer to the nth term in a sequence of numbers: T1, T2, ...
How do you read 12 hole ocarina music?
12 hole ocarina music is just the same as any other music. You read the dots, and play the notes. Of course you will need to know the proper finger positions for each note, and know the name of each note. First things first, to hold your ocarina, have your left palm facing you, your four fingers on the holes on the top, and your left thumb over the hole on the left side on the bottom of the ocarina. Then, place your right hand over the other side, covering the top holes with your fingers, and your thumb covering the other bottom hole. For the purpose of this answer, I will be referring to the fingers and holes L1 L2 L3 L4 ___________ ,--- o o o o ---.... | ---. |__ __o o o o___---` \_/ R1 R2 R3 R4 T1 T2 o o Now, I will list the primary note names as well as their finger positions: B - All fingers down (including the tiny little holes above L3 and R3) C - Everything but the tiny little holes D - Everything but R4 and the tiny little holes E - Everything but R3, R4, and the tiny little holes F - Everything but R2, R3, R4, and the tiny little holes. G - T1, T2, L1, L2, L3, L4 A - T1, T2, L1, L2, L4 B - T1, T2, L1, L4 C - T1, T2, L4 D - T2, L4 If you want any of the sharps and/or flats of these notes, just experiment. You now know the main notes on an ocarina, and are completely free to practise to your heart's content.
What is a T2 hyperintense foci?
Type your answer here... it is a T2 hyperintense foci
How many earth years does it take mercury to orbit around the sun?
You use T2=R3 r=Au and mercury has 1/3 AU so you take 1/3 to the 3 and then take that answer and squre it. It came up to about 1 so it would be 1 year
A sample of air has a volume of 140ml at 67degrees Celsius At what temperature will its volume be 50ml at constant pressure?
V1/T1 = V2/T2 Where temperature must be in Kelvins 67C + 273 = 340 K So 140/340 = 50/T2 Find T2 340/140(50) = T2 T2 = 121 K or -152C
What are the fingerings for g major scale on the double french horn?
If you start on the G on the second line on the staff and then go to the G above the staff, the fingerings go like this: 0-T12-T2-T0-T12-T2-T2-T0-T2-T2-T12-T0-T2-T12-0 (G, A, B, C, D, E, F#, G, F#, E, D, C, B, A, G)
If a space probe were sent into an orbit around the sun that brought it as close as 0.5 AU to the sun and as far away as 5.5 AU what would its orbital period be?
By Kepler's 3rd Law, The square of the time period is directly proportional to the cube of the length of the semi-major axis of the elliptical orbit. T2 = K R3In our Solar system, if length is expressed in AU and time in years, the constant K = 1. The length of the major axis is 0.5 + 5.5 = 6Hence, length of semimajor axis = R = 6/2 = 3 * T2 = R3 * T2 = 33 * T2 = 27 * T = 271/2 * T = 5.196 years The orbital period would be 5.196 years Kepler's Law calculations are found at the link.
T2?
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