You cannot add 4 odd NUMBERS to make an odd number, so you have to think constructively...eg 1 + 3 + 15 = 19. There are other similar solutions...
It is even. Both numbers end with odd digits and two odd digits always add to an even number. You can see that is the case in this instance.377 + 87 = 464
There are no four consecutive whole numbers that add up to 35. The sum of two consecutive [whole] numbers is an even number plus an odd number which is an odd number. The sum of two consecutive numbers and the two next consecutive numbers is the sum of two odd numbers which is even, but 35 is odd, so no four consecutive whole numbers cannot add up to 35.
Add together all the digits in the odd positions in the number. Sum = A Add together all the digits in the even positions in the number. Sum = B If A-B is 0 or if it divisible by 11 (positive or negative), then the original number is divisible by 11.
The sum of the digits in odd position minus the sum of the digits in even position is divisible by 11.
Add the digits together. The sum of the digits of 23 is 5.
22, 2+2= 4 and half of 22 is 11 which is odd
You can work this out pretty quick; just assemble the number in parts. We know the number must be odd, so the last digit has to be an odd one. Let's make it three: 3 Now we need to add five more digits that collectively add up to seven (giving us the sum of ten for our six digits. There's no limit of repetition limit, so we can simply say our numbers are 1, 1, 1, 2 and 2: 111223 That's our last six digits that add up to ten. To get four different eight-digit odd numbers, all we have to do is add four combinations of two digits on the beginning: 99111223 98111223 97111223 96111223
It is even. Both numbers end with odd digits and two odd digits always add to an even number. You can see that is the case in this instance.377 + 87 = 464
If ( p ) is an integer between 1000 and 1030, it can be expressed as ( p = 1000 + n ), where ( n ) ranges from 0 to 30. The sum of the digits of ( p ) is given by ( 1 + \text{(sum of the digits of } n) ). Since 1 is odd, for the total sum of the digits to be odd, the sum of the digits of ( n ) must be even. As a result, if ( p ) is odd, ( n ) must be odd (e.g., 1, 3, 5, etc.), confirming that ( p ) is indeed odd. Thus, the statement is true: if the sum of the digits of ( p ) is odd, then ( p ) must be odd.
There are no four consecutive whole numbers that add up to 35. The sum of two consecutive [whole] numbers is an even number plus an odd number which is an odd number. The sum of two consecutive numbers and the two next consecutive numbers is the sum of two odd numbers which is even, but 35 is odd, so no four consecutive whole numbers cannot add up to 35.
2222
5 odd numbers CAN'T add up to an even number like 50
Add the digits together. The sum of the digits of 23 is 5.
Add together all the digits in the odd positions in the number. Sum = A Add together all the digits in the even positions in the number. Sum = B If A-B is 0 or if it divisible by 11 (positive or negative), then the original number is divisible by 11.
odd
The sum of the digits in odd position minus the sum of the digits in even position is divisible by 11.
Add the digits together. The sum of the digits of 23 is 5.