-499
7,14,28,35,42,49,56,63,70,77,84,91,98,105,112,119,126,133,140,147,154,161,168,175, 182,189,196,203,210,217 hey please add 7 after 217 and 7 after it.. you'll get the numbers..
The sum of the first 500 counting numbers (1-500) is 125,001.
There's a trick to this one. Let 1 + 2 + ... + 500 be the sum of all integers 1 to 500, called X Now, imagine we want to add the sum the integers from 1 to 500 and to the sum of the integers from 1 to 500. This would give us 2*X we can write it as 1 + 2 + ... + 500 + 1 + 2 + ... + 500 But that's not particularly useful. What if we look at it as: 1 + 2 + ... + 499 + 500 + 500 + 499 + ... + 2 + 1 adding the numbers that are directly on top of each other, we get 500 + 1 = 501, 499 + 2 = 501... 1 + 500 = 501 Thus every term is 501, and we have 500 terms. So, we have 501*500 = 2X Thus X, the sum from 1 to 500, is (500*501)/2 = 125,250
There are 232 numbers between 1 and 500 that are divisible by 3 or 5.
-499
500
Sum of first n numbers = n/2(n +1) = 500 x 1001 = 500500
Add them up.
7,14,28,35,42,49,56,63,70,77,84,91,98,105,112,119,126,133,140,147,154,161,168,175, 182,189,196,203,210,217 hey please add 7 after 217 and 7 after it.. you'll get the numbers..
The sum of the first 500 counting numbers (1-500) is 125,001.
There are 63 numbers 1 to 500 that are divisible by six but not by eight.
There's a trick to this one. Let 1 + 2 + ... + 500 be the sum of all integers 1 to 500, called X Now, imagine we want to add the sum the integers from 1 to 500 and to the sum of the integers from 1 to 500. This would give us 2*X we can write it as 1 + 2 + ... + 500 + 1 + 2 + ... + 500 But that's not particularly useful. What if we look at it as: 1 + 2 + ... + 499 + 500 + 500 + 499 + ... + 2 + 1 adding the numbers that are directly on top of each other, we get 500 + 1 = 501, 499 + 2 = 501... 1 + 500 = 501 Thus every term is 501, and we have 500 terms. So, we have 501*500 = 2X Thus X, the sum from 1 to 500, is (500*501)/2 = 125,250
if you add 1+1 it = 2 get it :D
1 000 500
There are 232 numbers between 1 and 500 that are divisible by 3 or 5.
500.5 Because: 1+2+3+.......998+999+1000 Add 1 to 1000 equaling 1001. This makes a pair. There are 500 more of these so 500 pairs. So 1001x500= 500500 Finally divide it by 1000 because there are 1000 numbers. (1000-1=999+1=1000) Concluding the answer to be 500.5 :)