cu(II) + 2agcl --> 2ag+cucl2
A two - degree -of -freedom gyroscope -AG
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meaning to multiply something into a term x. for example, this term x can be (3+a), or even (a+b+c+8). let us name that something 'y'. to expand, we put y(x), meaning y times x. another example, -g(a) = -ag, or minus (a times g). if the set x contains more than one term, multiply all the terms by y. y(a+b) = ay + by.remember, minus times minus is a plus, and minus times plus is minus.
Ksol = [Ag+]2*[CO32-] at equilibrium (saturated solution)in which:Ksol is the thermodynamic equilibrium constant, onlydependent on temperature.[X] is the concentration of substance X in mole/Litre.Note that:the exponent 'p' in the expression [X]p is equal to the number of ions in the balanced equilibrium equation: 2Ag+ + CO32- (Ag2CO3)s. So p=2 for [Ag+]concentration of only solved particles are in the Eq. expression [Ag+]2*[CO32-] and not those of solid (Ag2CO3)s. However, some solid (Ag2CO3)s is needed to get to an equilibrium state, so at least the solution is to be saturated.
The compound AgN doesn't exist; the silver nitride is Ag3N.
The formula for the ionic compound formed between silver (Ag) and nitrogen (N) would be Ag3N. This is because silver has a +1 charge and nitrogen has a -3 charge, so the compound requires three silver ions for every one nitrogen ion to balance the charges.
The molecular formula for silver oxide is Ag2O.Silver oxide is a fine black, or sometimes brown, powder which is used to prepare other silver compounds.
cu(II) + 2agcl --> 2ag+cucl2
the solution is supersaturated
Sodium (Na) has been reduced.
The formula for silver sulfate is Ag2SO4. It consists of two silver ions (Ag+) and one sulfate ion (SO4^2-).
In the cell, the half-reaction for silver will be Ag+ (aq) + e- -> Ag (s) with a standard reduction potential of +0.80 V. The half-reaction for copper will be Cu2+ (aq) + 2e- -> Cu (s) with a standard reduction potential of +0.34 V. The silver half-reaction will occur at the cathode, while the copper half-reaction will occur at the anode in the cell.
Ag+
The ionic name for the compound AgI is silver iodide, where "Ag" represents the silver cation and "I" represents the iodide anion.
The oxidation half-reaction is: 3Ag --> 3Ag^+ + 3e^-
Silver (Ag)