The standard form of the equation of a line is written as: Ax + By = C, where A, B, and C are real numbers, and A and B are not both 0.
When we want to graph an equation that is written in general form, we can solve the equation for y and write the equation in slope-intercept form.
Example: Transform the equation 2x + 4y = 8 into its slope-intercept form, and graph the equation.
Solution:
2x + 4y = 8 subtract 2x to both sides;
4y = - 2x + 8 divide by 4 to both sides;
y = - (1/2)x + 2 This is the slope-intercept form (y = mx + b) of the equation 2x + 4y = 8.
The coefficient of x, -(1/2), is the slope, and the y-intercept is 2. Now we are able to graph the line using the fact that the y-intercept is 2, and the slope is -(1/2).
Start at the point (0, 2), go to the right 2 units and then down 1 unit (since the slope is -(1/2))to the point (2, 1). Then draw the line that passes through the points (0, 2) and (2, 1).
y = mx + b where m is the slope and b is the y-intercept
Well its not slop, but slope and its adjective form is sloppy.
4x - 5y = 0 standard form of slope intercept line equation is y = mx + c m = slop and c = intercept rewrite the 4x - 5y = 0 in standard form y = 4/3 x compare it with standard form, and slope = 4/5
the y intercept is -3 so the y axis at (0,-3) hope that helps and the slop is 1 so the graph will start at (0,-3) and go up one and to the right one and keep going
-6x = 2y - 120 -2y -2y -2y - 6x = -120 +6x +6x -2y = 6x - 120 -2y/-2 = 6x/-2 - 120/-2 y = -3x + 60
y = mx + b where m is the slope and b is the y-intercept
It is the intercept.
It stands for the y-intercept. where it crosses the y axis ... this might help http://id.mind.net/~zona/mmts/functionInstitute/linearFunctions/lsif.html
The line will be going 'uphill' from left to right
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No, a vertical line cannot be written in slope-intercept form, which is expressed as (y = mx + b), where (m) is the slope. Vertical lines have an undefined slope because they run parallel to the y-axis, meaning they do not change in the x-direction. Instead, a vertical line can be represented by the equation (x = k), where (k) is a constant.
It is: y = x+3 whereas 1 is the slope and 3 is the y intercept
Well its not slop, but slope and its adjective form is sloppy.
'Slop' you are being very 'sloppy' with your English spelling. The word is 'Slope'. Note the mute 'e'. 6x + 5y = 5 To find the slope/intercept we algebraically rearrange. The general slope/intercept equation is of the form ' y = mx + c '. Where 'm' is the slope, and 'c' in the intercept on the y-axis'. Hence 6x + 5y = 5 => 5y = -6x + 5 (Note the change of sign to (-). y = (-6/5)x + 5/5 y = (-6/5)x + 1 So the slope is ' -6/5' or ' -1 1/5 ' or '1.2'. The intercept on the y-axis is y = 1.
slop intercept form is y=mx+b where m is the slope. We have to find b. To do so we have to evaluate the problem. We see that the y-intercept is 3 which means the coordinate pair (x,y)=(0,3). Plug (0,3) into the question. it should like this 3=m(0)+b. now solve. anything times 0 is 0 so the equation is now 3=b. now we have m, which is -2 and b which is 3. plug it into the equation and the slop intercpet form is y=-2x+3 =D
If you mean: x+y = -9 then y = -x-9 whereas the slope is -1 and the y intercept is -9