(a) y = -3x + 1
Graph the following Inequalities: x > 3
Differentiation of the function would give you an instantaneous rate of change at one point; the tangent line. Repeated differentiation of some functions would give you many such points. f(x) = X3 = d/dx( X3) = 3X2 =======graph and see
If x2 and x3 are meant to represent x2 and x3, then x2 times x3 = x5 You find the product of exponent variables by adding the exponents.
The inverse of a number is 1 divided by that number. So the inverse of x3 + 1 is 1/(x3 + 1).
A line graph needs an equation. x-2 and x3 are expressions: neither is an equation.
x3
x3
(a) y = -3x + 1
Graph the following Inequalities: x > 3
The graph is a diagonal line with a slope of 1, passing through the x-axis at (3, 0) and the y-axis at (0, -3), extending from the lower left to the upper right.
use the horizontal line text, a horizontal line intersects the graph of x3 -3 only once so it is one to one.
linear: LINE example--- line non-linear: not a LINE example--- parabola The other possibility is a graph with a non-linear scale. First a linear scale will have each unit represent the same amount, regardless of where you are on the scale. A semilog scale, has a linear scale in the horizontal direction, and a logarithmic scale in the vertical direction. Exponential functions (such as ex & 10x), will graph as a straight line on this type of graph scale). A logarithmic or log-log scale, has logarithmic scales on both horizontal and vertical axis. Power functions (such as sqrt(x), x2 and x3), graph as a straight line on these scales. See Related Link
y = x2 is an (approximately) U shaped graph that is entirely above the x axis and is symmetric about the y axis. y = x3 is asymptotically negatively infinite when x is negatively infinite and positively infinite when x is positively infinite. It is symmetric about the line x+y=0.
Differentiation of the function would give you an instantaneous rate of change at one point; the tangent line. Repeated differentiation of some functions would give you many such points. f(x) = X3 = d/dx( X3) = 3X2 =======graph and see
Differentiation of the function would give you an instantaneous rate of change at one point; the tangent line. Repeated differentiation of some functions would give you many such points. f(x) = X3 = d/dx( X3) = 3X2 =======graph and see
Yes, y = -x3+1 is a function. You can graph it and see that it passes the vertical line test. See related link, below.