You take the derivative of the function. The derivative is another function that tells you the slope of the original function at any point. (If you don't know about derivatives already, you can learn the details on how to calculate in a calculus textbook. Or read the Wikipedia article for a brief introduction.)
Once you have the derivative, you solve it for zero (derivative = 0). Any local maximum or minimum either has a derivative of zero, has no defined derivative, or is a border point (on the border of the interval you are considering).
Now, as to the intervals where the function increase or decreases: Between any such maximum or minimum points, you take any random point and check whether the derivative is positive or negative. If it is positive, the function is increasing.
The answer depends on whether it is uniform motion, motion under constant acceleration, motion under constantly increasing (decreasing) acceleration, or something else. Since you have not bothered to provide that crucial bit of information, I cannot provide a more useful answer. The answer depends on whether it is uniform motion, motion under constant acceleration, motion under constantly increasing (decreasing) acceleration, or something else. Since you have not bothered to provide that crucial bit of information, I cannot provide a more useful answer. The answer depends on whether it is uniform motion, motion under constant acceleration, motion under constantly increasing (decreasing) acceleration, or something else. Since you have not bothered to provide that crucial bit of information, I cannot provide a more useful answer. The answer depends on whether it is uniform motion, motion under constant acceleration, motion under constantly increasing (decreasing) acceleration, or something else. Since you have not bothered to provide that crucial bit of information, I cannot provide a more useful answer.
Cause
Yes. A cubic equation can have 3 real roots. Depending on their size, each of three intervals could contain a root. In that case different intervals must give different roots.Yes. A cubic equation can have 3 real roots. Depending on their size, each of three intervals could contain a root. In that case different intervals must give different roots.Yes. A cubic equation can have 3 real roots. Depending on their size, each of three intervals could contain a root. In that case different intervals must give different roots.Yes. A cubic equation can have 3 real roots. Depending on their size, each of three intervals could contain a root. In that case different intervals must give different roots.
Geologists have divided Earth's history into a series of time intervals. These time intervals are not equal in length like the hours in a day. Instead the time intervals are variable in length. This is because geologic time is divided using significant events in the history of the Earth.
Histogram
You take the derivative of the function, then solve the inequality:derivative > 0 for increasing, orderivative < 0 for decreasing.
It depends on the function.
There are many families of functions or function types that have both increasing and decreasing intervals. One example is the parabolic functions (and functions of even powers), such as f(x)=x^2 or f(x)=x^4. Namely, f(x) = x^n, where n is an element of even natural numbers. If we let f(x) = x^2, then f'(x)=2x, which is < 0 (i.e. f(x) is decreasing) when x<0, and f'(x) > 0 (i.e. f(x) is increasing), when x > 0. Another example are trigonometric functions, such as f(x) = sin(x). Finding the derivative (i.e. f'(x) = cos(x)) and critical points will show this.
The intervals are determined by when the derivative is positive or negative, because the derivative is the slope and a negative slope means the function is decreasing. The function y=(x/sqrt(x2))+1, however, can be rewritten as y=x/absolutevalue(x) + 1, and as such will be represented as a pair of parallel lines, y=0 for x<0 and y=2 for x>0. As the lines are horizontal, the function is never increasing or decreasing.
Intervals & dilation determine how soon baby arrives.
Intervals are one of the best exercises in strengthening your heart. Intervals puts healthy stress on your heart increasing blood flow and overall health.
The answer depends on whether it is uniform motion, motion under constant acceleration, motion under constantly increasing (decreasing) acceleration, or something else. Since you have not bothered to provide that crucial bit of information, I cannot provide a more useful answer. The answer depends on whether it is uniform motion, motion under constant acceleration, motion under constantly increasing (decreasing) acceleration, or something else. Since you have not bothered to provide that crucial bit of information, I cannot provide a more useful answer. The answer depends on whether it is uniform motion, motion under constant acceleration, motion under constantly increasing (decreasing) acceleration, or something else. Since you have not bothered to provide that crucial bit of information, I cannot provide a more useful answer. The answer depends on whether it is uniform motion, motion under constant acceleration, motion under constantly increasing (decreasing) acceleration, or something else. Since you have not bothered to provide that crucial bit of information, I cannot provide a more useful answer.
It depends on what needs inspection. All items have certain safety functions to be performed at certain intervals.
There are an infinite number of confidence intervals; different disciplines and different circumstances will determine which is used. Common ones are 50% (is the event likely?), 75%, 90%, 95%, 99%, 99.5%, 99.9%, 99.99% etc.
try sqrt(N) where N represents the number of observations you have...
f(x) is decreasing on the interval on which f'(x) is negative. So we want: (x2-2)/x<0 For this to be true either the numerator or the denominator (but not both) must be negative. On the interval x>0, the numerator is negative for 0<x<sqrt(2) and the denominator is positive for all x>0. On the interval x<0, the denominator is negative for all values on this interval. The numerator is positive on this interval for x<-sqrt(2). So, f' is negative (and f is decreasing) on the intervals: (-infinity, -sqrt(2)), (0, sqrt(2))
that many of the physical and chemical properties of the elements tend to recur in a systematic manner with increasing atomic number.