First write down the problem neatly using the below format:
102 / 2 = ____
the ____ is where you are going to write the result
Now copy dovn the first digit from the left end of the numerator (102)
102 / 2 = ____
1
Is this number smaller than the divisor (2)
yes it is, so we pull down the second digit
102 / 2 = ____
10
Ten is bigger than 2 so now you divide 2 into 10
2 goes into 10 five times so write 5 as the first digit of the result
102 / 2 = 5___
10
now multiply the resultdigit by the divisor and write the resulting
number under the 10. then subtract that number from 10
102 / 2 = 5___
10
10
0
pull down the next digit to stand behind the 0
102 / 2 = 5___
10
10
02
this number is not smaller than the divisor so we divide it by 2
and write the result of dividing as the second digit of the result
102 / 2 = 51__
10
10
02
again multiply the resultdigit by the divisor and write the resulting
number under the 02. then subtract that number from 02
102 /2 = 51__
10
10
02
2
0
there are no more digits to pull down, so you have finished dividing 102 by 2. The result is 51.
This is called long division
regards JakobA
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One example of such a sum involving positive integers is: 204/2 = 102
Yes. If you divide 102 by 3 you get 34. 3x34=102
102
To answer this you divide 102 by 94% 102 / .94 The answer is a non ending decimal. Rounded to the nearest tenth it is : 108.5
102