To find the total number of integers between 100 and 300 that are divisible by 3, we first determine the smallest and largest integers in this range that are divisible by 3. The smallest integer divisible by 3 is 102, and the largest is 297. To find the total number of integers between 102 and 297 that are divisible by 3, we calculate (297-102)/3 + 1, which equals 66. Therefore, there are 66 integers between 100 and 300 that are divisible by 3.
The first whole number divisible by 3 is 102 and the last one 399. Let n be the number of whole numbers between 102 and 399 102 + (n - 1)x3 = 399 (this is an arithmetic progression) Solving n, n-1 = (399 - 102)/3 = 99 n = 100 Since even whole numbers among these 100 will be divisible by 6, the number not divisible is half of 100, i.e. 50. regards, lpokbeng
No.
102.
102, 105, 108, 111 and just keep adding three until you get to 399.
102 is divisible by: 1 2 3 6 17 34 51 102.
102 For a number to be divisible by 6, it must be divisible by both 2 and 3. 102 div by 2 = 51; 102 div by 3 = 17
102 as 102/2 = 51 102/3 = 34
The factors of 102 are 1, 2, 3, 6, 17, 34, 51, and 102. So it is composite with eight factors.
102
102.
Yes 102 is indeed divisible by 6. A simple way to find out if a number is divisible by six is the divisibility rules. For 6, Check if the number ends in a even number such as 0, 2, 4, 6, or 8. Then, add the digits of your number and check if it is any number which is a multiple of 3. For example, 102 ends in 2 1+0+2=3 102 is divisible by 6.
Yes. Every non-zero number is divisible by itself.
102
102 is divisible by 1, 2, 3, 6, 17, 34, 51, 102.
The first whole number divisible by 3 is 102 and the last one 399. Let n be the number of whole numbers between 102 and 399 102 + (n - 1)x3 = 399 (this is an arithmetic progression) Solving n, n-1 = (399 - 102)/3 = 99 n = 100 Since even whole numbers among these 100 will be divisible by 6, the number not divisible is half of 100, i.e. 50. regards, lpokbeng
100 is divisible by 1, 2, and 5. 1 is not itself a prime number; 101 is a prime; 102/2 =51 102/3 =34 102/17=6