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How many whole number between 100 and 400 are divisible by 3 but not divisible by 6?
The first whole number divisible by 3 is 102 and the last one 399. Let n be the number of whole numbers between 102 and 399 102 + (n - 1)x3 = 399 (this is an arithmetic progression) Solving n, n-1 = (399 - 102)/3 = 99 n = 100 Since even whole numbers among these 100 will be divisible by 6, the number not divisible is half of 100, i.e. 50. regards, lpokbeng
Is 102 divisible by 9?
No.
Smallest three digit number divisible by 6?
102.
What numbers between 100 and 400 are divisible by 3?
102, 105, 108, 111 and just keep adding three until you get to 399.
What is 339 divisible by?
It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.It is divisible by 3, for example.
What is 102 divisable by?
102 is divisible by: 1 2 3 6 17 34 51 102.
What is the smallest 3 digit number divisible by 6?
102 For a number to be divisible by 6, it must be divisible by both 2 and 3. 102 div by 2 = 51; 102 div by 3 = 17
What is the smallest 3 digit number divisible by 2 and 3?
102 as 102/2 = 51 102/3 = 34
What are the factors of 102?
The factors of 102 are 1, 2, 3, 6, 17, 34, 51, and 102. So it is composite with eight factors.
What is the smallest 3 digit number that is divisible by 3?
102
What is the next number after 99 that is divisible by 3?
102.
Is 6 divisible by 102?
Yes 102 is indeed divisible by 6. A simple way to find out if a number is divisible by six is the divisibility rules. For 6, Check if the number ends in a even number such as 0, 2, 4, 6, or 8. Then, add the digits of your number and check if it is any number which is a multiple of 3. For example, 102 ends in 2 1+0+2=3 102 is divisible by 6.
Is 102 divisible by 102?
Yes. Every non-zero number is divisible by itself.
What is the smallest three digit number divisible by both 2 and 3?
102
What is 102 as a product of its prime factors?
102 is divisible by 1, 2, 3, 6, 17, 34, 51, 102.
How many whole number between 100 and 400 are divisible by 3 but not divisible by 6?
The first whole number divisible by 3 is 102 and the last one 399. Let n be the number of whole numbers between 102 and 399 102 + (n - 1)x3 = 399 (this is an arithmetic progression) Solving n, n-1 = (399 - 102)/3 = 99 n = 100 Since even whole numbers among these 100 will be divisible by 6, the number not divisible is half of 100, i.e. 50. regards, lpokbeng
What is the smallest three digit number that is divisible by three primes?
100 is divisible by 1, 2, and 5. 1 is not itself a prime number; 101 is a prime; 102/2 =51 102/3 =34 102/17=6
