nCr=n!/r!/(n-r)!
If you have N things and want to find the number of combinations of R things at a time then the formula is [(Factorial N)] / [(Factorial R) x (Factorial {N-R})]
6^4 = 1296 combinations but some are repeatable e.g. 1221 = 2121 = 2112 etc. so for the total number of non repeatable combinations with 4 dice, use pascals triangle to get 126 unique combinations.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
If the combinations don't require numbers to be in specific spots such as 2+3 being different then 3+2, then all the possible combinations with what was listed include: 6+6 2+2+2+6 2+2+2+2+2+2
There are 10,737,573 combinations and you must think I am mad if you think I am going to list them!
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Whoever asked this question you spelled combinations wrong and combinations are what are used to see how many pairs or groups you can make out of objects.
Four combinations: tam ham mat hat Hope it helps (:!
Ask your teacher or anyone else who knows how to do it!?!
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If you have N things and want to find the number of combinations of R things at a time then the formula is [(Factorial N)] / [(Factorial R) x (Factorial {N-R})]
If the 6 digits can be repeated, there are 1296 different combinations. If you cannot repeat digits in the combination there are 360 different combinations. * * * * * No. That is the number of PERMUTATIONS, not COMBINATIONS. If you have 6 different digits, you can make only 15 4-digit combinations from them.
The math term for combinations refers to the selection of items from a larger set where the order of selection does not matter. It is typically denoted as "n choose k" or C(n, k), where n is the total number of items and k is the number of items to choose. The formula for combinations is C(n, k) = n! / (k!(n-k)!), where "!" denotes factorial, the product of all positive integers up to that number.