2log4(7x) - 5 = 0 2log4(7x) = 5 log4(7x) = 5/2 7x = 45/2 =(41/2)5 = 25 = 32 x = 32/7
7x -39 = -32
65 = 2x - 7x 65 = -5x 65/-5 = -5x/-5 -13 = x
7x-4=x+2 7x=x+2+4 7x=x+6 7x-x=6 6x=6 X=1
X = 0 and -11/36
32= -3 - 7x 32 + 3 = - 7x 35= - 7x 35/7 = -x 5 = -x -5= x
X = 5 7x5 = 35 - 3 = 32
7x = 18 - 2x 7x + 2x = 18 9x = 18 x = 2
Here is the work for that problem. 7x+6= 41 7x=41-6 (subtracting 6 from both sides) 7x=35 x=5
2log4(7x) - 5 = 0 2log4(7x) = 5 log4(7x) = 5/2 7x = 45/2 =(41/2)5 = 25 = 32 x = 32/7
x=12
The club has 56 old men. Let x = number of old men Then x-16 = number of young men (the old men outnumber the young men by 16) 7x = 9(x-16) +32 (7 times the # old men is 32 more than 9 times the # young men) 7x = 9x - 144 + 32 7x = 9x - 112 7x + 112 = 9x - 112 + 112 7x + 112 = 9x 7x - 7x + 112 = 9x - 7x 112 = 2x 56 = x (the # of old men)
x=0
The answer to the math problem -3 7x plus 7 is x equals 1/3.
7x -39 = -32
2x = 7x - 10 subtract the 7x from both sides 2x - 7x = -10 -5x = -10 divide both sides by -5 x = 2
7x + 8 = 5x + 327x = 5x + 242x = 24x = 12hope this helps