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Q: How do you evaluate 6n plus 4 and 6n plus 4 for n3?

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2 + 6n + 4, with n = 10 then 2 + 6(10) + 4 2 + 60 + 4 62 + 4 66

12m + 9n - 4 - 10m + 6n = 2m + 15n - 4

6n - 4 - 3 = 3n + 10 + 4n -7 = 7n - 6n + 10 -17 = n

n3 + 3n2 + 4n + 12 = (n3 + 3n2) + (4n + 12) = n2(n + 3) + 4(n + 3) = (n2 + 4)(n + 3).

6n + 4 = 40(Minus 4 on both sides)6n = 40 - 46n = 36(Divide by 6 on both sides)n = 36/6= 6

3n+2+3n+2=6n+4

6n -3=2n+9 6n-2n=9+3 4n=12 n=12/4 n=3

M+6n

6 + (the quotient of a number and 4) =6 + (number ÷ 4)=6 + (N÷4) =⁶/₁ + ⁿ/₄ =²⁴/₄ + ⁿ/₄ =²⁴ⁿ/₄ =24n ÷ 4 =6n ÷ 1 =6n

6n take-away 4 = 2

32 4 plus 2 the third power -3 cannot be evaluate.

Move the 2n over the equals sign. Become 4n (as 6n-2n= 4n) and then if 4n=16 then n=4.

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