We need to first move the decimal two (2) places to the left:
480 = 4.80 x 102
The 2 in 102 comes from how many places we moved the decimal. It's positive because the number it represents is larger (480 > 4.8)
With one significant figure, we need to round to the nearest whole number:
5 x 102
The answer is 5 x 102
0.0357 has three significant figures. A significant figure is any non-zero digit or any embedded or trailing zero. Leading zeros are not significant.
Truncated to one significant figure, it's 9,000 .Rounded to one significant figure, it's 10,000.
1000 is written with one significant figure, with only the 1 being a significant figure.
It has 1 significant figure.
The significant figure 2.00 has to do with the certainty of a measurement.
6.21 with one significant figure is just 6
As a product of its prime factors in exponents: 218 = 262144
50
2 significant figures.
I DONT FREAKING KNOW BRO
The answer is 6*10^5 g.
(if there is to be one significant figure) 2 * 102(if there are to be two significant figures) 2.0 * 102 (if there are to be three significant figures) 2.00 * 102
To three significant figure, 483.54 becomes 484. The rule when rounding off numbers is "If the first figure to be discarded is 5 or more then the previous figure is increased by 1". Expressed in Scientific Notation, 484 becomes 4.84 x 102.
0.0357 has three significant figures. A significant figure is any non-zero digit or any embedded or trailing zero. Leading zeros are not significant.
The significant figure of 37.753 to 1 significant figure is 40.
7 billion in Scientific Notation = 7 x 109To express a number in scientific notation, you first need to divide it by a power of 10 such that the greatest significant figure is in the units place. In this case, that can be done by dividing 7 billion by 1 billion to give 7. Next, the power of ten that was used should be placed alongside as a multiplication. We used 1 billion, which is the 9th power of 10. Thus, 7 billion in scientific notation is 7x109
you take the last digit in the first one and add/subtract it to the last digit in the second one and that is your answer